Question

VOLTAGE-DIVIDER BIAS 179 CONFIGURATION h determined in Example 4.7. Essentially, exact and approximate techniques is the ten the 07 step down transformer and a load RL of 820 ohms. It is connected to an ac source of 100 VAC rms, 50 Hz. (hint: note the rms values, and for diode PIV, assume ideal diodes and draw the PIV eqv ckts) ve rectifier circuit has a 10:1 3. A positive output, a. Draw this circuit.. b. Find Vp and Vave at the load RL and the diode PIV for this case. c. If a filter capacitor CF of 100 uf is added, draw the new circuit, and assuming vp at the load is now 10 V peak, find Vrpp and Vave at the load and the diode PIV for this specific case ,Ma

Answer 1

assue diode is dea, Nstre iO ma ave

PIV4 Vpeak DOMF 3204 Peaヒコ lov Peak l O Sox 8 20 x 100 Xtb

ave oo change? even-though Capacitos is added