Question

The air in a 75 cubic metre kitchen is initially clean, but when Laure burns her toast while making breakfast, smoke is mixed with the room's air at a rate of 0.04 mg per second. An air conditioning system exchanges the mixture of air and smoke with clean air at a rate of 4 cubic metres per minute. Assume that the pollutants are mixed uniformly throughout the room and that burnt toast is taken outside after 42 seconds. Let S(t) be the amount of smoke in mg in the room at time t (in seconds) after the toast first began to burn.

a. Find a differential equation obeyed by S(t).

b. Check that the solution is correct using S(12).

c. Check what is the level of pollution after 42 seconds, correct to 10 significant figures (do not incude units)

d. The time, in seconds, when the level of pollution falls to 0.004mg per cubic metre is ____________ seconds.

e. Find S(t) for 0≤t≤42 by solving the differential equation in (a) with an appropriate initial condition.

f.. What is the level of pollution in mg per cubic meter after 42 seconds?

g. How long does it take for the level of pollution to fall to 0.004 mg per cubic metre after the toast is taken outside?

Answer 1

he ais na 75 cubic metye kitchen is nitia clean, ut uhen laure buins he st hile makin break tast, smoke CCiwen that in a kitchen air - 7s cubic metre changina air and snok e rate Let sct) be the amount Smok e in 4he Toom at time 'P' after he tosis be o burn inding ditterencial equation obejed b Sct) is , means d t 4S00

ondiion is. 4S OD - 180 - 4sCt) S 00 d t 112S d sct 112S 0 452S -t12S Q S -t112S tl 112S

O Jewel popul ation in mA pen cubic metre e ate 42 S ec -92/112.5 4S X 0.036 こ 1.62 m The dwel g population S(42): l' is atter t〉, 42 d S(t)_ -S d t 1125 d t 112S 1-6 2 t. 12S 0 1-6 2 12 S 1.62 125 I. 62

ㅏ.62 t s -Jn7 5xo.oo eC. 0.0 0