The loor system shown below is subjected to a uniform load of q 120 psf. All connections are shea...
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The structural steel framing plan of the figure represents a floor system for a narrow commercial building. The floor is to support a 6 in. thick reinforced concrete slab, a live load of 150 psf and an additional future load of 20 psf. Use the Allowable Stress Design (as per the class reference materials) and ASTMA36 steel for all members, use 0.6 Fy as...
each floor and the roof are also shown in the ?gure. All columns are A992 steel (Fy=50 ksi All connections between girders, beams, and columns are simple pins and the supports on the ground level are pinned in both directions 20 ft PLAN C1 20 ft C3 30 ft 30 ft ID=20 psf, qL,-12 psf 12 ft ID=50 psf, qL,-60 psf ELEVATION 12 ft qD=50 psf, qL,-60 psf 16 ft C2, C3 C1
1. For the building shown below, calculate the dead load, reduced live load, and maximum design load per IBC 2012, LRFD load combinations. Beam loads should be in plf, column loads should be in kips. [To be done by hand.] Note: It is acceptable check only equations 16-1 and 16-2 of IBC 2012. a. Beam I b. Веam II olumn A/3-supporting 1 story d. Column B/2- supporting 1 story C e. Column B/2-supporting 4 stories Given loading: Dead Load 60...
The floor system shown has a dead load that includes: Floor tile and bedding 17 psf 2VLI20 (2" deep metal deck with 42" of concrete on top) Mechanical ducts = 4 psf Electrical 1 psf Gypsum board ceiling 3 psf Beam self-weight is given by its name (ie. W16x26 is 26 plf) Girder self-weight is given by its name (ie. W30x90 is 90 plf) The floor live load is 150 psf. 45 psf 1. Determine the end reactions for Beams...
The floor system of school classroom is shown below. Determine the total load acting on all beams, girders, and columns. STEEL COLUMN W16X100 GIRDER 4 INCH CONCRETE SLAB W8X40 BEAM 12 ft 6 ft
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The floor system shown below consists of normalweight concrete (150 pcf). Beams C2 ! LT 1 7.0 inch ! h=20 in G2! 12 in Girders BI 1 7.0 inch Slab 8 ft span h 24 in ----- - -- - --- 15 in 15 ft 15 ft Use 4000 psi concrete and Gr. 60 reinforcing steel. Assume 0.75 inch clear cover. Include concrete self-weight and a superimposed dead...
Using the Letter R so Dead load is 160 and Live load is
50
by 120 floor Design Problem: 150 girders Floor System: oor (Design for Bending onl nding only.ust beams and 120'x 150', Columns on a 30 Grid 1) 2) Girders span from Column to column in the 150 foot direction 3) Beams span between girders 4) Concrete floor spans across beams Loading: See table on following page Elements/Materials: 1) Beams: S-Shape a. Use same beam throughout b. No...
Questions 5-8
A steel frame shown below is subjected to combined uniformly distributed gravity load (w 2 kips/f) and a horizontal earthquake load of H-10 kips Both the beams and the columns are made of W12x120 section having a yield strength of F 45 ksi. The Young's modulus of steel s E-29,000 ksi. The distributed load w is used to simulate the self-weight of the beam, the load transferred from roof slab, as well addition superimposed dead loads. The self-weigh...
Wood Deck Plan: Part Π-Shear & Bending Moment Diagrams Wood Deck Framing Plan-Dimensions & Loading Uniformly Distributed Load STUDENTI "A" No. (feet) (feet) (feet) (feet)(inches) Dead Load (#/ft*) Live Load (#/ft2) 30 10 15 15 15 15 18 18 18 18 18 12 14 16 12 14 16 12 14 16 12 16 12 16 12 16 12 16 12 16 12 10 10 10 12 12 12 12 30 5 40 40 50 50 30 30 40 40 5...
Wood Deck Plan: Part Π-Shear & Bending Moment Diagrams Wood Deck Framing Plan-Dimensions & Loading Uniformly Distributed Load STUDENTI "A" No. (feet) (feet) (feet) (feet)(inches) Dead Load (#/ft*) Live Load (#/ft2) 30 10 15 15 15 15 18 18 18 18 18 12 14 16 12 14 16 12 14 16 12 16 12 16 12 16 12 16 12 16 12 10 10 10 12 12 12 12 30 5 40 40 50 50 30 30 40 40 5...