Question

2 pts DQuestion 7 For arachadic acid calculate the total number of FADH2 and NADH molecules, respectively, that are formed in the B-oxidation and subsequent utilization of CoA in the TCA cycle. Reference figure 23.16 when calculating these values. 19,39 14, 26 O 2,5 12, 12 C-SCoA 7 CoA, 7 [FAD], 7 NAD B-Oxidation 7 [FADH21, 7 NADH +7H 8 Acetyl-CoA 100 ADP 100 Oxidative Electron transport phosphorylation 100 ATP 24 NADH, 8 [FADH TCA cycle >16 CO2 →8AIP FIGURE 23.16 Reduced coenzymes produced by B-oxidation and TCA cycle activity provide electr that drive the synthesis of ATP in oxidative phosphorylation. Complete oxidation of palmitoyl-Co yields a total of 108 ATP. Subtracting the 2 ATP equivalents consumed in forming the original Co thioester, oxidation of palmitate produces 106 ATP

Answer 1

1. 19, 39

Palmitic acid is a 16 carbon compound which produces 8 Acetyl Co-A molecules on oxidation which yields 7 NADH and 7 FADH₂ on $\beta$ - Oxidation. The subsequent entry of these Acetyl co-A molecules into TCA cycle produces 24 NADH and 8 FADH₂

$\beta$ - Oxidation

for 16 carbon compound

8 Acetyl co-A molecules produced and for these 7 NADH and 7 FADH₂

TCA cycle

for 8 Acetyl co-A molecule

x3 = 24 NADH and x 1 = 8 FADH₂ molecules

A total of 31 NADH and 15 FADH₂ molecules as given in the diagram

Like wise for a arachidic acid which is a 20 carbon compound

It splits into 10 Acetyl co-A molecules

For these molecules in $\beta$ - Oxidation 9 NADH and 9 FADH₂ molecules would produce

For these 10 molecules entered into TCA 30 NADH and 10 FADH₂ molecules would produce

and hence a total of 39 NADH and 19 FADH₂ would produce through $\beta$- Oxidation and TCA cycle.