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12. Let A = CD , where C is an invertible n × n matrix and A and D are n × n matrices. Prove that the matrix DC is similar to
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Answer #1

Two matrices M and N are similar if there exist a matrix P such that

N = P^{-1}MP

Here:

M = DC

and

N = A

So,

To prove:

We can find matrix P such that:

A= P^{-1}DCP                               (1)

Since given:

A= CD                                        (2)

Substituting (2) in equation (1), we get:

To prove:

CD= P^{-1}DCP                            (3)

Choose:

P = D                                                      (4)

Substituting (4), equation (3) becomes:

CD= D^{-1}DCD

= I\times CD=CD

where I is the Identity Matrix.

Thus, we note that by choosing P=D, equation (1) is satisfied.

Thus, we prove that the matrix DC is similar to A.

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