Homework Answers
Solution:
The address range of 24LC256 is found as follows from the datasheet. The 24LC256 has 256 Kbit/8 = 32 Kbyte of storage, so the address range is 0x0000-0x7FFF. It has a page write buffer of 64 bytes size that means the individual page addresses are range from 0x0000 to 0x003F, 0x0040-0x007F, etc.
Each page contains 64 Bytes locations and address range 0x0000-0x003F.
Each page start address is the multiple of 64.
It is given that 0x244F = 9295 in decimal.
It is divided by 64 gives the page number = 9295/64 = 145.234375
It means that the given address is in the page number 146 page starting from 1st page.
Address range of 146 th page is = 0x2440 - 0x247F.
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7. The 24LC256 EEPROM chip has 64 byte pages. Which page contains memory address 0x244F?
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Question 2 Suppose you have a byte-addressable virtual address memory with 8 virtual pages of 64 bytes each and 4 page frames. Assuming the following page table, Page = Frame Valid Bit 0 0 1 2 3 4 5 What physical address corresponds to the virtual address 0X44 a. OXC1 b.OXC2 COXC4 d. OXCO OXC3
Consider a logical address space of 8 pages; each page is 2048 byte long, mapped onto a physical memory of 64 frames.
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