If a computer has 64-bit addresses and each address corresponds
to one byte, how many gigabytes of memory can the computer address?
(Show the math)
The past answers for this same question are either incorrect or do not show the math.
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let's suppose you have 3 bits how many numbers can you represent using these 3 bits?
1st bit 0 or 1 = 2 choices
2nd bit 0 or 1 = 2 choices
3rd bit 0 or 1 = 2 choices
so total 2*2*2 = 8 numbers
in the same way, if you have n bits then you can represent 2*2*2*.....2(n times )= 2n numbers
given each byte is represented by one 64 bit address
total bytes = total number that 64 bits can represent = 264
we know 210 bytes = 1KB
220= 1 MB
230= 1GB
total memory the computer address is 264/ 230 GB = 234 GB
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