Question


Write a stoichiometric conversion factor relating the number of hydrogen ions displaced from the ion exchange resin to the nu
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Answer #1

Let us consider that resin is R​​​​​​- and it is in acidic form, R-H+

Here R- represent that the resin is functionalised with negatively charged species like COO​​​​- , SO​​​​​3​​​​- etc so that it can attract the positively charged ions. According to the question the resin is in H+ form. Now when other positive ions will pass through the resin, it will be exchanged by H+ ions.

As Cu2+ is a divalent cation it will displace two H+ ions from the resin.

The equation can be written as

2R-H+ + Cu​​​2+ = R2Cu + 2H+

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