Find the Steady State Voltage and Current Values.
Develop the equation for i(t) , the current through the inductor and Vout(t).
I need help, I don't know if my calculations are correct, I found the neper frequency to be: a=439.109 rad/sec and resonant frequency to be Wo=14586.5 rad/sec.
This is a parallel step response RLC circuit
The circuit is underdamped.
Please show all work clearly so that I can understand the process.
Find the Steady State Voltage and Current Values. Develop the equation for i(t) , the current thr...
I need help to find the values! gures below (a-d), determine the values for R1, R2, voltage or type of op-amp based on the information listed. You may ors with an open circuit, short circuit, or values 1kn SRS1Mn. gain, voltage, a) 76 k2 Type: Non-Inverting Vout max R1 (based on Voutmas) 0.3V Type: Inverting, Av =-100 V/V Vin- b) R1 12V R1 12V Type: Buffer Vout- R1 =- c) +10 V R1 ーVout -10 V Type: Av- IV R2...
1) An input step voltage Vin(t)=10 u(t) Volt is applied to the circuit shown below. The initial voltage on the capacitor is zero. Using Laplace transform techniques, calculate the resulting output voltage Vout(t). R1 R2 Vout 2000 Vin c1 1000 1uF R3 1000
2502 In the adjoining circuit schematic, in steady-state, the current flowing through the loop causes a voltage drop across the resistor, having the waveform vr(t) = 15 cos (75 t) and a voltage drop across the capacitor given by ve(t) = 20 cos (75 t +90°) (a) Express the above two voltages in phasor form. (b) Find the source voltage shown in the circuit schematic, expressed in phasor form. (c) Express the source voltage v(t) as a function of time....
the voltage of the battery is 12V, and the values of the resistances are R1=5 ohms, R2=10 ohms, R3= 15 ohms, and R4= 20 ohms. Answer the following questions: 1. R1 and R3 are in : 2. R2 and R4 are in: 3 Compare the magnitude of the current through R2 and R3. which is greater? 4. Compare the magnitude of the voltage across R1 and R3. which is greater? 5. Compare the magnitude of the voltage across R2 and...
MA C2 Vin out R2 Component Values: R1 = 2k , R2 = 10㏀, Cl = C2 = 1nF Consider the filter circuit above. Assume that the operational amplifier is ideal (infinite gain and infinite input impedance) Problem 2: Derive the transfer function of the circuit, H(s) - Vout(s)Vin(s)
In the adjoining circuit schematic, in steady-state, the current flowing through the loop causes a voltage drop across the resistor, having the waveform vR(t) = 15 cos (75 t) and a voltage drop across the capacitor given by vC(t) = 20 cos (75 t + 90⁰) (a) Express the above two voltages in phasor form. (b) Find the source voltage shown in the circuit schematic, expressed in phasor form. (c) Express the source voltage v(t) as a function of time....
For the next set of questions, consider the following circuit. The switch has been open for a long time. At t=0, it is closed. t=0 11 R1 3 1 3 C c IL R2 3 V = Assume the following values: 11=5mA 12=10mA R1=2K R2=2k L1=10mH C1 = luF Find the following: a) 11(0), the initial current through the inductor (in mA): b) The final current thru the inductor after the switch has been closed for a long time (in...
2.5 kΩ 5H 3.0 uF The initial voltage at t<0, V40)-100 v and current i(0)-0. At t=0 the switch is closed. a. (10 points) Find a differential equation (in time domain) for the voltage across the inductor. (10 points) The following expression is the solution for the differential equation find in part b. Determine all the parameters in the solution α, A, B and ω. b. V()e (A Cos(ot)+ BSin(r)) c. (2 points) Determine the steady state current and the...
For the amplifier circuits in Figs.3 and 7: a. Write an expression for the output voltage, vo, in terms of the resistor symbols and the input voltage, vin. ---For the first circuit (Fig. 3), the feedback resistor is the series combination of R2 and R3. Use both of these resistor symbols in your expression. -- For circuit 2 (Fig. 7), assume that vin = 5V and ignore potentiometer R1 and C3. b. Using resistor values and input voltage amplitudes, calculate...