Calculate ΔG° for the reaction. Convert the answer from kJ to kcal 4NH, (8) +50, (g) 4 NO (g) + 6...
0%-1010 kJ/mol,xn eaction 1: 4NH 3(8) +5 0(8)4 NO(8) + 6 H2O0D) Reaction 2: 2 NO 2(8) 2 NO(8) + 02(g) Reaction 3: 4 NO 28)+O2(8)+2 H2OD4 HNO3a)AG 10kJ/moln Based on the values of ΔG° for the three reactions represented above, what is the value of for the reaction represented below? 4 NH,(8) +802(8) 4 HNO ,(aq)+4 H,OO) (A) -1040 kJ/mol (B) -1110 kJ/mol, (C) -1250 kJ/mol (D) -1320 kJ/mol an 2 NO(8)N,048)
Consider the two reactions. 2 NH,(g) + 3 N, O(g) - 4N, (g) + 3H,O(1) 4NH,(g) + 30,(g) — 2N, (g) + 6H, 0(1) AH = -1010 KJ AH = 1531 kJ Using these two reactions, calculate and enter the enthalpy change for the reaction below. N,(g) + 40,(8) NO(g) AH- AHL
QUESTION 19. 1 POINT From the following balanced equation, 4NH,(g) +50,(g) + 4 NO(g) + 6H, O(1) how many moles of H, O can be formed when 4.5 mol NH, react with 2.5 mol 0,2 Select the correct answer below: 2.5 mol O 2.0 mol O 3.0 mol O 6.8 mol FE
Consider the reaction: 4NH,00) + 50 (8) 4NO(g) + 6H2O() Using standard thermodynamic data at 298K, calculate the free energy change when 2.00 moles of NH3(g) react at standard conditions. AG ΓΧη Submit Answer Ray Eatin Grun man name
Calculate ΔG°(in kJ/mol) for the reaction NO2(g) + H2O(l) --> HNO3(l) + NO(g). (unbalanced) Question 7 Calculate AG°(in kJ/mol) for the reaction NO2(g) + H2O(0) --> HNO3(1) + NO(g). (unbalanced) Substance AGF(kj/mol) NO2(g) 51.8 NO(g) 86.7 HNO3(0) -79.9 H2O(l) -237.2 Write answer to two significant figures and correct sign.
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ Calculate ΔG°rxn for the following reaction. 18 NO(g) → 6 N2O(g) + 6 NO2(g) -3.83 kJ -23.0 kJ 138 kJ -138 kJ 23.0 kJ
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ Calculate ΔG°rxn for the following reaction. 18 NO(g) → 6 N2O(g) + 6 NO2(g) -3.83 kJ -138 kJ 23.0 kJ -23.0 kJ 138 kJ
Calculate ΔG°, in kJ, for the following reaction: 2 HNO3 (liq) + NO (g) → 3 NO2 (g) + H2O (liq) Substance ΔGf° (kJ) HNO3 (ℓ) −79.71 NO (g) 86.57 NO2 (g) 51.30 H2O (ℓ) −237.18
14) Calculate ΔG. and KP for the following equilibrium reaction at 25C 2H,0(g)2H2(g) +0-(8) AGi value is-228.6 kJ/mol for H20(g).
Calculate ΔG°(in kJ/mol) for the reaction NO2(g) + H2O(l) --> HNO3(l) + NO(g). ( unbalanced) Substance ΔGfo(kJ/mol) NO2(g) 51.8 NO(g) 86.7 HNO3(l) -79.9 H2O(l) -237.2 Write answer to two significant figures and correct sign.