Diseussion Questions 1. The open-chann form of glucose constitutes only a small fraction of any a...
Diseussion Questions 1. The open-chann form of glucose constitutes only a small fraction of any aqueous glucose sample (-002%. Yet when Cu" is used to oxidize the open-chain form, nearly all of the glucose in the sample reacts. Use Le Chatelier's Principle to explain this observation. 2. Both 3-bexanol fa sik-carbon alcohol) and hexanal (a sik-carbon aldehyde) are liquids at room temperature. Yet all aldohexoses are solids. a) Draw the structures of these substances below. Circle their polar/inonpolar groups, the type of attractive force it can use to interact with neighboring molecules. b) Explain the physical states of each compound, and predict which liquid (3-hexanol or hexanal) would have the higher boiling point. e) Both 3-hexanol and hexanal have difference in the water solubilities of these compounds limited water solubilities. Yet aldohexoses are extremely water-soluble. Explain the S C. Ngo 124
Diseussion Questions 1. The open-chann form of glucose constitutes only a small fraction of any aqueous glucose sample (-002%. Yet when Cu" is used to oxidize the open-chain form, nearly all of the glucose in the sample reacts. Use Le Chatelier's Principle to explain this observation. 2. Both 3-bexanol fa sik-carbon alcohol) and hexanal (a sik-carbon aldehyde) are liquids at room temperature. Yet all aldohexoses are solids. a) Draw the structures of these substances below. Circle their polar/inonpolar groups, the type of attractive force it can use to interact with neighboring molecules. b) Explain the physical states of each compound, and predict which liquid (3-hexanol or hexanal) would have the higher boiling point. e) Both 3-hexanol and hexanal have difference in the water solubilities of these compounds limited water solubilities. Yet aldohexoses are extremely water-soluble. Explain the S C. Ngo 124