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4. Silver oxide is used in button batteries to power electric watches and other trinkets. These batteries generate a potentican u answer the following questions?

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4) Reduction at cathode : Ag+ (aq)+ e- -----------------> Ag(s) Eo = 0.342 V

Oxidation at anode : Zn(s) -----------> Zn2+ (aq) + 2e- Eo = + 1.249 V

---------------------------------------------------------------------------------------

Zn(s) + 2Ag+ (aq)  -----------------> Zn2+ (aq)+ 2Ag(s)

Ecell = Eoreduction of reaction at cathode+Eooxidation of reaction at anode

= 0.342 V + 1.249 V

= + 1.591 V

Ecell = + 1.591 V

no of electrons transferred n = 2

We know that ΔGcell = -nFEcell , F = 9.65 x 104 C/mol

  ΔGcell = -2 x 9.65 x 104 C/mol x 1.591 V

   = - 307063 J

= - 307 kJ

ΔGcell = - 307 kJ

Therefore,

ΔGcell = - 307 kJ

5)   

Reduction at cathode : Cu2+ (aq)+ 2e- -----------------> Cu(s) Eo = 0.34 V

Oxidation at anode : Zn(s) -----------> Zn2+ (aq) + 2e- Eo = 0.76 V

---------------------------------------------------------------------------------------

Zn(s) + Cu2+ (aq)  -----------------> Zn2+ (aq) + Cu(s)

Eocell = Eoreduction of reaction at cathode+Eooxidation of reaction at anode

= 0.34 V + 0.76 V

= + 1.1 V

Ecell = + 1.1 V

no of electrons transferred n = 2

Zn(s) + Cu2+ (aq)  -----------------> Zn2+ (aq) + Cu

Given that [Cu2+]= 0.1 M , [Zn2+]= 19.0 M

Ecell = Eocell - (0.059/n) {Iog [Zn2+ (aq)]/[Cu2+ (aq)]}

= 1.1 - (0.059/2) log {[19.0]/ [0.1]}

= + 1.03 V

Ecell = + 1.03 V

Therefore,

Ecell at 25oC is  + 1.03 V

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