solve for q max, min, and intermediate bearing pressure at the bottom of the foundation
Weight of the Footing = (Unit Wt. of Concrete)*(length)*(breadth)*(depth)
= (14.126 kN/m3)*(1.5 m)*(1.5 m)*(0.6 m)
= 19.07 kN
Now, because of the moment we will have non-uniform bearing
pressure across the footing,
Eccentricity (e) = (30) / ( 160 + 19.07)
= 0.167
Again, since the water table is at he bottom of the footing, we
can assume pore water pressure to be 0.
Therefore, Min Bearing Pressure (q min) =
{((160+19.07)/1.5) - 0 }*{ 1- ((6*0.167)/1.5)}
= (172.713)*(0.332)
= 38.30 kN/m2
Max Bearing Pressure (q max) = {((160+19.07)/1.5) - 0 }*{ 1+ ((6*0.167)/1.5)}
= (172.713)*(1.668)
= 192.44 kN/m2
Intermidiate Bearing Pressure = (192.44 + 38.30)/2 = 115.37 kN/m2
Solve for q max, min, and intermediate bearing pressure at the bottom of the foundation
The time for 50% consolidation of a 25 mm thick clay specimen (drained at top and bottom) in the laboratory is 150 sec. How long (in days) will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 75% consolidation? There is an impermeable shale layer at the bottom of the clay layer in the field I. 2. Use Figure 1 for the following Compute the vertical effective...