1. (3 points) Consider the hydrogen atom in the 2p state, What is the probability that the electr...
Consider an electron within the ls orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by normalized probability = [az-e * (až + 2a, R+ 2R)] where a, is the Bohr radius. For a hydrogen atom, ao = 0.529 Å. What is the probability of finding an electron within one Bohr radius of the nucleus? normalized probability: 0.323 Why is the probability of finding...
Question 1: Consider the following situation: For the hydrogen atom in its ground state pictured on the right, classically orbiting at the Bohr Radius 20 = 5.29 + 10-11m, calculate: a) The speed the electron is traveling at. b) The angular momentum 1 =7 x 5 of the electron. Compare it to = 1.055 10-34J.s. c) The magnetic field due to the electron at the position of the proton. Is it into the page or out of the page? on-...
An electron is in the 2p state of a hydrogen atom. Using the radial solution: find: a) the expectation value of r b) the most probable value of r c) the classical maximum possible radius of the electron d) the probability of finding the electron at a distance greater than in part (c)
B.2 [10p]. Consider the ground state of the Hydrogen atom. Compute the probability of finding the electron in a spherical region of radius 1 Ă around the proton. Uground (r, 0,0) = - e-r/ro ћc with ro = 0 am.c2 VT23/2 er/ (1.5)
for an electron in a Hydrogen atom: 2) Consider the electron in a 2p state (for simplicity, take M = 0) (i) Consider whether <r> and <1/r> can be calculated by integrating only the radial part of the wavefunction. (ii) Calculate the expectation value of the distance between the electron and the nucleus, (ii) Calculate the expectation value of the reciprocal distance between the electron and the nucleus, <1/r>. (iv) Are the average potential energies of the electron in 2s...
Calculate the average orbital radius of a 3d electron in the hydrogen What is the atom. Compare with the Bohr radius for a n 3 electron probability of a 3d electron in the hydrogen atom being at a greater radius than the n 3 Bohr electron?
The ground-state wave function of a hydrogen atom is: where r is the distance from the nucleus and a0 is the Bohr radius (53 pm). Following the Born approximation, calculate the probability, i.e., |ψ|^2dr, that the electron will be found somewhere within a small sphere of radius, r0, 1.0 pm centred on the nucleus. ρν/α, Ψ1, () =- Μπαρ
2. The hydrogen atom [8 marks] The time-independent Schrödinger equation for the hydrogen atom in the spherical coordinate representation is where ao-top- 0.5298 10-10rn is the Bohr radius, and μ is the electon-proton reduced mass. Here, the square of the angular momentum operator L2 in the spherical coordinate representation is given by: 2 (2.2) sin θー sin θ 00 The form of the Schrödinger equation means that all energy eigenstates separate into radial and angular motion, and we can write...
Based on the solutions to the Schrödinger equation for the ground state of the hydrogen atom, what is the probability of finding the electron within (inside) a radial distance of 2.7a0 (2.7 times the Bohr radius) of the nucleus? The answer is supposedly .905. Can anyone elaborate on how and why?
Calculate the probability of an electron in the ground state of the hydrogen atom being inside the region of the proton. (For purposes of calculation, use a proton radius r = 0.960 x 105 m. Hint: Note that r << an.) X