Question

Supose Bowman is the first week, it is paid Si50 for crashing it the second week, it is paid $125: for crashing it the third week, it is paid S100, for crashing it any additional weelks, it is 575 per week. What is the minimum cost schedule and what is the cost of the project based on this schedule 1 9:03 LTE 星期二 下午9:59 编辑 12-24 Bowman Builders manufactures steel storage sneas for commercial use. Joe Bowman, president of Bowman Builders, is contemplating producing sheds for home use. The activities necessary to build an experimental model and related data accompanying table are given in the to NORMAL CRASH NORMAL CRASH COST COST IMMEDIATE ACTIVITY TIME TIME 1,000 1,600 2,000 2.700 300 300 3 1,300 1,600 850 1,000 14,000 5,000 2 1.500 2.,000 D. E the project. For crashing it i Suppose Bowman is paid additional money for crashing the first week, it is paid S150; for crashing it the second week, it is paid S125; for crashing it the third week, it is paid S100, for crashing it any additional weeks, it is $75 per week. What is the minimum cost schedule and what is the cost of the project based on this schedule.

Answer 1

Solution :

Minimum cost schedule is 12 weeks with cost of 10,825

Predeces Normal ras Norma Crash Crashing Iteration Iteration Iteration Activity sor cost/day ES 600.0 700.0 Time Cost Cost EF LS LF Slack Path Duration 1 1000 1600 0 OADG 2 BEG 11 CF 14 13 12 2700 12 300 N/A 1600 1000 50001000.0 2000 250.0 1300 75.0 10 10 0 Activity Crashed 2 Crash Cost 11 Cum. Crash Cost 0Normal Cost D, E $75$1225 $75150$275 10,950$10,950$10,950 $10,950 850 50.0 $75 12 14 D, E 1500 10 10 $275-5375 S10,950$10,875$10,825$10,850 $0-$150$ Payment for Crashin Total Cost Critical Path ADG Duration 14