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(1 point) Use power series to solve the initia-value problem 2n+1 2n Answer: y- n-0

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Answer #1

, such that Apply the reverse producl implif Evaluate the integas: 2x yx-cwher Muriply beth sices by at substue 2 x pphy the

Y(x) = e^(-x^2)

We know the expansion of e^(x) as 1+x+x^2 / 2! + X^3 / 3! +...

Substitute in place of x , - x^2

We obtain 1-x^2 + x^4 /2! -x^6 / 3! + ...

The first blank is (-1)^n /(n!) Second blank is 0

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