Question

help me. I've been looking at this textbook problem for an hour. I'm stuck at the last part. how does the question turn the uncoupled system

(2z-2+3e^t) to the linear differential

z(t) = c1e^2t +e^3t +1

dobe Acrobat Reader DC ④ 315 (133 of 91 1)ト:@ Θ θ 129%·x-甲甲2 105 Solution of X'-AX+G315 This is 221-2+ 6z2 +2+3e This is an uncoupled system, consisting of one differential equation for just z, and a second differential equation for just z. Solve each of these first-order linear differential equations to obtain Then 421o c + (-ke-10/3 2/3 This is the general solution in the form 2(0)C+Vp, which is a sum of the general solution of the associated homogeneous equation and a particular solution of the nonhomogeneous equation. ECTION 10.3 PROBLEMS

Answer 1

3t @ohist.)e 呟7-TS27際"p2-A2 ,50lved Hoon gnons "X aud. C3

8t 8t 3T5 (e 3 с5e3t Rob becomes 3t