SOLUTION
1) C is correct
Both common cause and special cause (Because two points lies outside the upper control limit
2) Option A is correct
With in variation basically an estimate of short term variation calculating an average range
3)Option C is correct
Overall variation is estimate of long term variation calculating the estimate of standard deviation based on all samples put together
4) True capability analysis make sense
5) It is false because value of Cp=0.35 process is not capable
6) it is false process is not centered on target
7) yes it is normal distribution it is true
8) false it has only 2 special cause bariation
9) True
10) true
Process Capablity Sixpack Report for Suppa 1. The process for supplier 2 is operaing under a. Com...
Section Two (True/False) Regarding SPC and control charts: 3. Control limits and specification limits are both provided by the customer. cause variation SPC uses graphed statics to determine if a process has special Control limits for most control charts are set at 2 standard deviations. If a control chart signals special cause variation, the cause will also be known. One should work on reducing common cause variation while eliminating special cause variation. Critical process outputs that are measured on a...
1. How can a process be “in control” but not delivering what the customer wants? What is "process capability”? 2. If the LCL on a process is much greater than the LSL, will the customer tend to be “happy" or "disappointed” with the the results of this process? Why? 3. A) If Cp = 1.00, what % of good product is the process expected to deliver? Answer B) Complete the following: “A common minimum standard in industry is a Cp...
1. Design X-bar and R charts a control chart with "standards given" as an aimed-at mean of Xo = 4.0, Sigma = .0033, and Subgroup size -5. It is not necessary to sketch the control-chart since we have no points to put on it. Just specify, CL, UCL and LCL. That is the design. 2. Then find the probability of in-control nonconformance given, USL = 4.00995 and LSL 3.99005 3. Also, by theory, what is the Probability of an out-of-control...
1. Design X-bar and R charts a control chart with "standards given" as an aimed-at mean of Xo = 4.0, Sigma = .0033, and Subgroup size -5. It is not necessary to sketch the control-chart since we have no points to put on it. Just specify, CL, UCL and LCL. That is the design. 2. Then find the probability of in-control nonconformance given, USL = 4.00995 and LSL 3.99005 3. Also, by theory, what is the Probability of an out-of-control...
all in one I. Given the following table of coating weights for samples of size n-4: (a) Calculate the x 's and R's for samples 2 through & (b) Calculate the X and R values for all cight samples (c) Determine the appropriate constants that would be used with this data to constructx and R control charts, and calculate the control limits Range 18.5 17.9 19.6 22.2 16.5 19.0 2021.2 20.5 20.3 18.90 19.8 20.4 22.8 19.0 20.7 22.2 20.5...
1. Design X-bar and R charts a control chart with "standards given" as an aimed-at mean of Xo 4.0, Sigma 0033, and Subgroup size 5. It is not necessary to sketch the control-chart since we have no points to put on it. Just specify, CL, UCL and LCL. That is the design. 2. Then find the probability of in-control nonconformance given, USL 4.00995 and LSL = 3.99005 3. Also, by theory, what is the Probability of an out-of-control point when...
Question 15 (1 point) The process capability ratio (Cp) of a Six Sigma Program is 2. (The upper and lower specification limits are each 6σ away from the mean. True False
Statics help needed urgently ! part 1 part 2 Design X-bar and R charts a control chart with "standards given" as an aimed-at mean of Xo 4.0, Sigma.0033, and Subgroup size 5. It is not necessary to sketch the control-chart since we have no points to put on it. Just specify, CL, UCL and LCL. That is the design. Then find the probability of in-control nonconformance given, USL 4.00995 and LSL 3.99005 Also, by theory, what is the Probability of...
1. What is the UCL for the XBar chart based on the data below, with n=4, and ten set of samples for the weight of soft drinks are given. USL for the product is 355 g and LSL is 345. Daily production is 15000 units. Sample # Observations 1 352 348 350 351 2 351 352 351 350 3 351 346 342 350 4 349 353 352 352 5 351 350 351 351 6 353 351 346 346 7 348...