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Please explain with detailMatch the surfactants to the HLB you would expect for them, using the expression: HLB 7+(hydrophilic group numbers) - 2(hydro

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Answer #1

1) HO(CH2CH2O)10CH2OH

HLB = 7 + \Sigma (hydrophilic group numbers) - \Sigma (hydrophobic group numbers)

sum of Hydrophilic group numbers = 1.9 (OH) + 0.33X 10 (CH2CH2O) + 1.9 (OH) = 7.1

Sum of hydrophobic group number = 0.475

HLB = 7 + (7.1) - (0.475) = 13.625 = 13.6

2) CH3(CH2)13COOK

HLB = 7 + \Sigma (hydrophilic group numbers) - \Sigma (hydrophobic group numbers)

sum of Hydrophilic group numbers = 19.1 (-COOK) = 19.1

Sum of hydrophobic group number = 0.475 (CH3) + 13 X 0.475 (CH2) = 6.65

HLB = 7 + (19.1) - (6.65) = 19.45 = 19

3) N(CH2CH2CH2OH)3

HLB = 7 + \Sigma (hydrophilic group numbers) - \Sigma (hydrophobic group numbers)

sum of Hydrophilic group numbers = 9.4 (-N+3) + 3 X 1.9 (-OH) = 15.1

Sum of hydrophobic group number = 9 X 0.475 (CH2) = 4.275

HLB = 7 + (15.1) - (4.275) = 17.825 = 17.8

4) CH3(CH2)17OH

HLB = 7 + \Sigma (hydrophilic group numbers) - \Sigma (hydrophobic group numbers)

sum of Hydrophilic group numbers = 1.9 (-OH) = 1.9

Sum of hydrophobic group number = 0.475 (CH3) + 17 X 0.475 (CH2) = 8.55

HLB = 7 + (1.9) - (8.55) = 0.35 = 0.4

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