Question

use a Newman projection of the C3-C4 bond of 223-trimethy1-4-phenylhexane to show the most stable conformation first. Rotate through all of the eclipsed and staggered conformations. Using the energy values provided in the tables below calculate the relative energies of the different conformations. Plot the changes in energy in the graph diagram providd. Hint: Draw a 2D structure first and "bold" the bond viewed in your Newman projection. vided. 2D Structure Approximate Eclipsing Energy Values (kcal/mole) H Me Et i-Pr t-Bu Ph Br H 1.0 14 15 1.6 30 17 1.6 Me 1.4 25 27 3.0 85 33 28 Et 1.5 27 33 4.0 10.0 3. 3.1 i-Pr 1.6 3.0 40 7.8 13.0 8.1 3.6 t-Bu 3.0 85 100 13.0 23.0 13.5 9. Ph 1.7 33 3.8 81 135 83 42 Br 16 28 31 36 91 42 30 Some were estimated by mo. Approximate Gauche Energy Values (kcal/mole) Some were estimated by me. H Me Et i-Pr t-Bu Ph Br H 0 0 0.1 0.2 05 02 0.1 Me O 08 0.9 1.1 2.7 1.4 1.0 Et 0.1 09 1.1 16 3.0 1.7 1.2 i-Pr 0.2 1.1 16 24 35 21 16 s-Bu 0.5 2.7 30 3.5 7.2 39 3.3 Ph 02 14 1.7 2.1 3.9 2.7 1.9 Br 0.1 1.0 1.2 16 3.3 1.9 1.1 Newman projections: lowest PE Koq calculation

Answer 1

fん 0%. CH2" 내 Here all he hul Ph ecu PE = 9 +1.4+0.9 0-1 t 0.5 t39 +84 0,5ナ3.0 こ5.2 t 3.0 27,8 = 6.8 z) Pん Pん Cit PE- 13.5 t 2-7 tỉ PE= 3-9 3-oto-g 十0-2 4 1.4 F 13.1 VI)

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