Question

Project 10-2: Calculate a Supernet Complete the following steps to practice calculating a supernet 10 ON PROJECTS 1,. Starting with the network ID 192.16.20.0/24, what is the default Class C subnet mask for this network? Write this information both in decimal and in binary 2. How many additional network bits must be used for host information in order to have about 2000 hosts per supernet? Use the same formula you learned for calculating number of hosts on a subnet. Write the new supernet mask in binary and in decimal notation. 3. What is the CIDR notation for the network ID now?

Please answer only Question 2

Answer 1

As mentioned in the instruction of the question clearly, I am only answering question number 2.

2) In class C number of network ID bits = 24

Number of host ID bits = 8

We know that class C each network can have max (2⁸ - 2) = 254 hosts.

So we apply subnetting concept to divide a given network into subnets and these subnets are merged to create supernets.

So to have 2000 host in our supernet. We have to need 11 bits for hosts [as 2¹¹ = 2048]. So the requirement can be fulfilled if 11 bits are taken for the host ID and remaining bits for the network ID.

So the new supernet mask will be in binary = 11111111.11111111.11111000.00000000

(in the above supernet mask in binary the first 21 bits represent the net ID and for those 21 bits the value is '1' and the remaining 11 zero's represent the host ID.)

The equivalent IP address in Decimal will be = 255.255.248.0

Hope this helps.