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QUESTION 2 A probability distribution has a mean of 57 and a standard deviation of 1.4. Use Chebychev's inequality to find the value of c that guarantees the probability is at least 96% that an outcome of the experiment lies between 57- c and 57-c. (Round the answer to nearest whole number.) a. e. 9 Cliek Save and Submit to saue and submit. Click Save All Answers to save all answers. Save All Ar QUESTION 3 Find the variance of the probability distribution for the histogram: 26 20 16 16 Da. Var (X) = 4.65 b. Var (X)-4.28 ○ c. Var ( X) = 4.2625 0 d. Var (X) 40125 QUESTION 4 D. varA.28 c. Var (X) 4.2625 Dd. Var (X) 4.0125 QUESTION 4 The birthrates in the country for the years 1981-1990 are: Year |1981 |1982 |1983 |1984 |1985 |1986 |1987 1988 |1989- T990 Birthrate一一15.9-一15.5-5.5一一15.7-1 5.7ーー5.6 5.7 -5.9-16.2 (The birthrate is the number of live births/1,000 population.) Compute the mean, variance, and standard deviation of the random variable X CJa μ-14.87, Var(X)-0.12, σ-o.23 16.7- b,แ-12.00, Var(X)--0.29, ơ--044. CD c. 1-14.87, Var(X)--0.29, ơ-0.35. Od.μ-15.84, Var(X)-0.12, σ= 0.35 QUESTION 5 payforessay.net Ore Question Completion Status: QUESTION S Rosa Walters is considering investing $10,000 in two mutual funds. The anticipated returns from price appreciation and dividends (in hundreds of dollars) are described by the following probability distributions Mutual Fund A 1 poi Probability eturns .2 .3 .5 -4 10 Mutual Fund B Returns Probability .2 .2 Compute (in dollars) the mean and variance for each mutual fund. Mutual Fund A: μ-S660, Var(X)-$288,400; ○ a. Mutual Fund B: μ-S480, Var(X)-$121,600 Tabihty -2 .2 .2 Compute (in dollars) the mean and variance for each mutual fund. Mutual Fund A: μ-S660, Var(X)-$288,400; S a. Mutual Fund B: μ-S480, Var(X)-$121,000 Mutual Fund A: μ-S380, Var(X)-$288,870; b. Mutual Fund B: μ-S330, Var(X)-$121,430 Mutual Fund A: μ-S380, Var(X)-$288,870; Og Mutual Fund B: μ-S350, Var(X) = $121,250 Mutual Fund A: M $830, Var(x)- $289380 O "Mutual Fund B: μ-$4.8, Var(X)-$288,870 QUESTION 6 The number of Americans without health insurance, in millions, from 1995 through 2002 is summarized in the following table. The number of Americans without health insurance, in millions, from 1995 through 2002 is summarized in the following table. 1 1998 1999 2000 02 43.6 44.7 402 39.2 H1.1 3 1995 1996 1997 40.5 Year Americans 41.4 What is the standard deviation of Americans without health insurance in the period from 1995 through 20022 O a, σ = 1.20 million O b. σ-1.76 million Og ơ_ 41.71 million Od. σ-3.09 million e.Om 1.93 million QUESTION7 1 poin The mean annual starting salary of a new graduate in a certain profession is $43,000 with a standard deviation of $500. What is the probability that the starting salary of a new graduate in this profession will be between $39,500 and $46,500? Oa. At least 24 O b. At least Oc.At least 48 25 36 - 49 d At least S QUESTION 8 A survey was conducted by the market research department of the National Real Estate Company among 500 prospective buyers in a large metropolitan area to determine the maximum price a prospective buyer would be willing to pay for a house. From the data collected, the distribution that follows was obtained. Compute the standard deviation of the maximum price (in thousands of dollars) that these buyers were willing to pay for a house. Round the answer to the nearest integer. Maximum Price Considered, x 150 500 160 70 170 S0 180 190 20 250 270 320 (0) a. ơ-S1783 240.000 85 85 500 05 500 20 Oc.ơ: $46,711 Ndơ $42,163 Oc.ơ-$46,711 (Od.σ $42,163 Oe.σ $42, 228 QUESTION 9 The following table gives the scores of 30 students in a mathematics examination. 80-89 70-79 69 50-59 0-99 Scores 13 Students 3 Find the mean and the standard deviation of the distribution of the given data. Hint: Assume that all scores lying within a group interval take the midvalue of that group. O a-G-76.83 O b.a -4.90 c.ơ-9.55 Od.- 54.99 De. ơ-91.22 Save All Answers Click Save and Submit to save and submit. Click Save All Answers to save all answers. e-G-91.22 QUESTION 10 A probability distribution has a mean of 45 and a standard deviation of 1. Use Chebychev's inequality to estimate the probability that an outcome of the experiment lies between 43 and 47 O a. At least 0.8 b. At least 0.25 Oc. At least 0.75 Od. At least 0.04 e. At least 0.5 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Sa 6:31イ Done くiCloud Please answer all questions

Answer 1

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