Question
the following information for the Triaglycerol “Oleooleopalmityl glycerol (Oleooleopalmitin)”

chart below. Using the triglyceride that has been assigned to you, determine and present the following information regarding
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Answer #1

CH2-O-co-[CH2]15-CH3
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CHO-co-CH3(CH2)7CH=CH(CH2)7COOH
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CH2-O-co-CH3(CH2)7CH=CH(CH2)7COOH

Activation of the fatty acid to Acyl CoA = -2 ATP

Palmitic acid is a 16 carbon fatty acid.

Activation of the fatty acid to Acyl CoA = -2 ATP
Number of cycles in the Beta oxidation of palmitic acid goes is (16/2) -1 = 7
7 FADH2 = 7 X 2 ATP = 14 ATP
7 NADH = 7 X 3 ATP = 21ATP
Beta oxidation 7 cycle gives 8 Acetyl COA enter into TCA cycle In krebs cycle
Acetyl CoA oxidation in the Krebs Cycle = 3NADH, 1FADH2, 1GTP
1 FADH2 = 1 X 2 ATP = 2 ATP
3 NADH = 3 X 3 ATP = 9 ATP
1GTP                       = 1ATP
1 Acetyl COA in TCA cycle provides 12 ATP
8 Acetyl CoA x 12 ATP/Acetyl CoA = 96 ATP
Total palmitic acid ATP produces = 14+21+96-2 = 129 ATP

Oleic acid has one double bond and it is 18 carbon chain. So one less FADH2 is produced.
In these 9 aceyl coA, 7 FADH2 and 8 NADH.

Activation of the fatty acid to Acyl CoA = -2 ATP
7 FADH2 = 7 X 2 ATP = 14 ATP
8 NADH = 8 X 3 ATP = 24 ATP
9 Acetyl CoA x 12 ATP/Acetyl CoA = 108 ATP
Total oleic acid ATP produces = 14+24+108-2 = 144 ATP

So 2 oleic acid gives = 288 ATP.

1 Glycerol gives = 11 + 5 + 19 = 35 ATP

Total = 129 + 288 + 35 = 452 ATP

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