Question

I need help writing out the number (in decimal) for each field and the final bits representation in bits. I got 0x2021FFFF for addi, 0x10200001 for beq, and I am currently stuck on j. Please let me know if I got the first two right and explain how to do j. Thanks

The program below is written using the MIPS instruction set. It is loaded into memory at address 0xF000000C (all instruction memory addresses are shown below F000000C loop: addi $1, $1, -1 F0000010 F0000014 FO000018 done: beq 1, $0, done j loop Write out the number (in decimal) for each field (opcode, rs, rt etc) and the final bits representation in Hex. (Be sure to put down all your steps for partial credit in case you make some mistake at any steps) addi bea:

Answer 1

I hope this is what you wanted. If you have any doubt please let me know.

1st and 2nd instructions are correct

3rd j instruction has 32 bit format which has 6 bit opcode and 26 bit address. 6 bit opcode for j is 000010 which is 2 in decimal. while address in decimal is 3 how to obtain it, is explained in screen shot. and final hex becomes 0x08000003.

1st opcode of addi instruction is 001000 which is 8 in decimal. rs which is 00001 which is 1 in decimal. rt which is 00001 which is 1 in decimal and immediate has -1 in decimal. final hex value explained in screenshot.

2nd is beq which has opcode 000100 which is 4 in decimal. rs which is 00001 which is 1 in decimal .rt which is 00000 which is 0 in decimal and offset in decimal is 1. final hex value explained in screen shot.

if you still have any doubt please let me know.

divided by 4 is because instructions size is 32 bit which is 4 byte.(3rd screenshot)

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tbe and serset dvided by L s hasa value$I cotsichis ceoot bersef γを oo 001 00000 00 00G0 o0 heare-i becomes