Question

Problem 3 (25 points) Consider the set of empirical measurements of Pr/Pt given in the table system at 2.5 G㎐ below for an indoor a) Find th e path loss exponent (y) that minimizes the MSE between the simplified and the empirical dB power measurements, assuming that do-1 m and K is determined from the free space path loss formula at this do. b) Find the received power at 50 m for the simplified path loss model with this path loss exponent (v) and a transmit power of 1 mW (0 dBm). M-Pr/Pt Distance From Transmitter -50 dB 30 m - 75 dB 60 m Table 1-4: Path Loss Measurements Recall that the simplified path loss model is given by p(dBm)= Pt(dBm) +K (dB)-1Oy log10 a) and 4Ildo

Answer 1

Power measure ments 2. F(Y) Mede a where nl measured (4) the Pedh lss measurement at de tance d' and Pinau (da) Kor the path model r loss based om the simplified model at dr using the free space path liss Remulo 033 0.12. K--+0.40 dB --go .to-19구?r 40.to 17 18r

1-50-1-qo.qo-19-커Y)) 2. F(v) = 2. Fly: (-So +FO.to +14-7刊 + 1134.16 + 316-1284-yA-1230.5% 12.8g . 3 2 + S39-28 γ2-1S13-96T To find the received pover af s㎝ under SimPLthe4 Path (cA model 40.40-29.0+--69.幵dBrn