using excel data analysis tool for regression, following o/p is
obtained
SUMMARY OUTPUT | ||||||||
Regression Statistics | ||||||||
Multiple R | 0.960496 | |||||||
R Square | 0.922553 | |||||||
Adjusted R Square | 0.891574 | |||||||
Standard Error | 2.607284 | |||||||
Observations | 8 | |||||||
ANOVA | ||||||||
df | SS | MS | F | Significance F | ||||
Regression | 2 | 404.8854 | 202.4427 | 29.78005 | 0.001669 | |||
Residual | 5 | 33.98965 | 6.79793 | |||||
Total | 7 | 438.875 | ||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | 13.57335 | 4.251581 | 3.192543 | 0.024196 | 2.644317 | 24.50239 | 2.644317 | 24.50239 |
X1 | 0.949587 | 0.214177 | 4.433665 | 0.006805 | 0.399029 | 1.500145 | 0.399029 | 1.500145 |
X2 | -0.40008 | 0.277083 | -1.44391 | 0.208369 | -1.11235 | 0.312183 | -1.11235 | 0.312183 |
b)
the test statictic = 4.43
α=0.10
df=N-1 = 7
critical value= -1.89 and +1.89
since, test stat > critical value = 1.89, reject Ho
reject the null hypothesis, there is enough evidence to conclude
that there is a relationship between x1 and y
H0: ß2 = 0
H1: ß2 ╪0
test stat = -1.44
critical value= -1.89 and +1.89
do not reject the null hypothesis, there is not enough evidence to
conclude that there is a relationship between x2 and y
c) for x1
since, p-value=0.007 is less than α, reject the null
hypothesis.
there is enough evidence to conclude that there is a relationship
between x1 and y
for x2
since, p-value=0.208 is greater than α,do not reject the null
hypothesis.
there is not enough evidence to conclude that there is a
relationship between x1 and y
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