Following is the output of multiple regression analysis generated by excel:
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.952718261 | |||||
R Square | 0.907672085 | |||||
Adjusted R Square | 0.870740919 | |||||
Standard Error | 2.835799962 | |||||
Observations | 8 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 2 | 395.2911929 | 197.6455964 | 24.5774011 | 0.0025902 | |
Residual | 5 | 40.20880712 | 8.041761423 | |||
Total | 7 | 435.5 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 14.56188966 | 4.234494556 | 3.438873156 | 0.01845781 | 3.67677487 | 25.4470044 |
X1 | 0.928970703 | 0.211020378 | 4.402279595 | 0.00700692 | 0.38652555 | 1.47141585 |
X2 | -0.443986852 | 0.303407342 | -1.46333589 | 0.20324461 | -1.22392025 | 0.33594655 |
(b-c)
For variable x1:
Hypotheses are:
The test statistics is:
t = 4.40
The p-value is: 0.0070
The critical value of t using excel function "=tinv(0.05,5)" is: +/- 2.571
Since t > 2.571, reject H0
That is we can conclude that independent variable X1 is significant to the model.
For variable x2:
Hypotheses are:
The test statistics is:
t = -1.46
The p-value is: 0.2032
The critical value of t using excel function "=tinv(0.05,5)" is: +/- 2.571
Since -2.571 < t < 2.571, fail to reject H0
That is we can conclude that independent variable X2 is not significant to the model.
Consider the following set of deependent and independent variables. Complete parts a through c below. 11...
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