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Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three nor

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Answer #1

Here we have 3 groups and total number of observations are 8+10+5=23. So degree of freedom is

df= 23-3 = 20

(a)

Critical value of t for α 0.01 and df = 20 is 2.845. The Fisher's LSD Value is

LSD=t_{\alpha/2}\sqrt{MSE\left (\frac{1}{n_{1}}+\frac{1}{n_{2}} \right )}=2.845\cdot \sqrt{33.4\cdot \left (\frac{1}{n_{i}}+\frac{1}{n_{j}} \right )}

The required confidence interval is

xbari-xbarj absolute diff 7.5 7.5 7.1 xbarj 39.3 39.3 46.4 Upper limit Significant(Yes/No) 0 No No groups (i-j) mu1-mu2 mu1-m

(b)

Critical value for α 0.01 , df=20 and k=3 is

q=4.64

So Tukey's HSD will be

HSD=q\sqrt{\frac{MSE}{2}\left ( \frac{1}{n_{i}}+\frac{1}{n_{j}} \right )}=4.64\sqrt{\frac{33.4}{2}\left ( \frac{1}{n_{i}}+\frac{1}{n_{j}} \right )}

The required confidence intervals are:

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