a)
critical value of t with 0.01 level and N-k=12 degree of freedom= | tN-k= | 3.055 | |||
Fisher's (LSD) for group i and j = (tN-k)*(sp*√(1/ni+1/nj) = | 16.36 |
Lower bound | Upper bound | differ | ||
|xi-xj|-LSD | |xi-xj|-LSD | |||
-9.36 | 23.36 | not significant difference | ||
-15.36 | 17.36 | not significant difference | ||
-8.36 | 24.36 | not significant difference | ||
-8.36 | 24.36 | not significant difference | ||
3.64 | 36.36 | significant difference | ||
-4.36 | 28.36 | not significant difference |
CH13Q4 4 The following statistics are calculated by sampling from four normal populations whose variances are...
CH13 Q4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) r1 = 137, n1 = 4; Tz = 144, n2 = 4; = 136, n3 = 4; T4 = 124, n4 = 4; MSE = 57.4 a. Use Fisher's LSD method to determine which population means differ at a- 0.01. (Negative values should be indicated by a minus sign....
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the gtable.) X1 163, ni = 5; 2 = 171, n2 = 5; J3 = 166, n3 = 5; X4 = 158, n4 = 5; MSE = 41.2 a. Use Fisher's LSD method to determine which population means differ at a = 0.05. (Negative values should be indicated by a minus sign. Round intermediate...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x⎯⎯1x¯1 = 149, n1 = 10; x⎯⎯2x¯2 = 154, n2 = 10; x⎯⎯3x¯3 = 143, n3 = 10; x⎯⎯4x¯4 = 139, n4 = 10; MSE = 51.3 a. Use Fisher’s LSD method to determine which population means differ at α = 0.01. (Negative values should be indicated by a minus sign....
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x−1 = 15.1, n1 = 8; x−2 = 20.9, n2 = 9; x−3 = 28.0, n3 = 6; MSE = 28.6 a. Calculate 99% confidence intervals for μ1 − μ2, μ1 − μ3, and μ2 − μ3 to test for mean differences with Fisher’s LSD approach. (Negative values should be indicated...
CH13 Q3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) a. Calculate 99% confidence intervals for μ 1-2, μ1-#3, and μ2-#3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.) Population Mean Differences Can...
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x−1x−1 = 25.3, n1 = 8; x−2x−2 = 31.5, n2 = 10; x−3x−3 = 32.3, n3 = 6; MSE = 27.2 a. Calculate 95% confidence intervals for μ1 − μ2, μ1 − μ3, and μ2 − μ3 to test for mean differences with Fisher’s LSD approach. (Negative values should be indicated...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
Chapter 13 Analysis of Variance Saved Help Save & Exit Sub Check my work mode: This shows what is correct or incorrect for the work you have completed so far. It does not indicate c Return to questio 4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) 10 points z = 153, n1 =6; 2 164, n2 =6; 23=...
a. Given the following information obtained from four normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "f' to 3 decimal places.) SST = 78.95; SSTR = 18. 16; C = 4; n1 = n2 = n3 = n4 = 15 df ANOVA Source of Variation Between Groups Within Groups Total p-value 0.002 b. At the 10% significance level, what is...
Ch 13 Q1 Random sampling from four normally distributed populations produced the following data: (You may find it useful to reference the E Treatments -16 -10 -8-14-19 -10 -12 -15 14 -19 -16 DClick here for the Excel Data File a. Calculate the grand mean. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.) Grand mean b. Calculate SSTR and MSTR. (Round intermediate calculations to at least 4 decimal places and final answers...