The following statistics are calculated by sampling from four normal populations whose variances are equal: (You...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x−1 = 15.1, n1 = 8; x−2 = 20.9, n2 = 9; x−3 = 28.0, n3 = 6; MSE = 28.6 a. Calculate 99% confidence intervals for μ1 − μ2, μ1 − μ3, and μ2 − μ3 to test for mean differences with Fisher’s LSD approach. (Negative values should be indicated...
CH13 Q3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) a. Calculate 99% confidence intervals for μ 1-2, μ1-#3, and μ2-#3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.) Population Mean Differences Can...
CH13 Q4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) r1 = 137, n1 = 4; Tz = 144, n2 = 4; = 136, n3 = 4; T4 = 124, n4 = 4; MSE = 57.4 a. Use Fisher's LSD method to determine which population means differ at a- 0.01. (Negative values should be indicated by a minus sign....
The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x−1x−1 = 25.3, n1 = 8; x−2x−2 = 31.5, n2 = 10; x−3x−3 = 32.3, n3 = 6; MSE = 27.2 a. Calculate 95% confidence intervals for μ1 − μ2, μ1 − μ3, and μ2 − μ3 to test for mean differences with Fisher’s LSD approach. (Negative values should be indicated...
CH13Q4 4 The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the g table.) r1 = 137, n1 = 4; = 144, n2 = 4; X3 = 136, n3 = 4; 되 = 124, n4 4; MSE = 57.4 a. Use Fisher's LSD method to determine which population means differ at α=0.01. (Negative values should be indicated by a minus 10 points sign....
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the q table.) x⎯⎯1x¯1 = 149, n1 = 10; x⎯⎯2x¯2 = 154, n2 = 10; x⎯⎯3x¯3 = 143, n3 = 10; x⎯⎯4x¯4 = 139, n4 = 10; MSE = 51.3 a. Use Fisher’s LSD method to determine which population means differ at α = 0.01. (Negative values should be indicated by a minus sign....
Please help with b and c, thanks! A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table). SUMMARY Groups Count Average Column 1 6 0.89 Column 2 6 1.31 Column 3 6 2.35 Source of Variation SS df MS F p-value Between Groups 8.65 2 4.33 16.65 0.0002 Within Groups 3.83 15 0.26 Total 12.48 17 b. Calculate 99% confidence interval estimates of μ1 − μ2,μ1 − μ3, and...
The following data were obtained for a randomized block design involving five treatments and three blocks: SST = 490, SSTR = 310, SSBL = 95. Set up the ANOVA table. (Round your value for F to two decimal places, and your p-value to three decimal places.) Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Blocks Error Total Test for any significant differences. Use α = 0.05. State the null and alternative hypotheses. H0: At...
A one-way analysis of varlance experlment produced the following ANOVA table. (You may find it useful to reference the g table). SUMMARY Count Groups Column 1 Column 2 olumn 3 Source of Variation Between Groups Within Groups Total Average 8.89 1.31 2.35 SS 8.65 df 15 17 MS 4.33 0.26 16.65 8.6882 12.48 a. Conduct an ANOVA test at the 1% significance level to determine if some population means differ. o Reject Ho, we can conclude that some population means...