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pUI) FOU are to write a function which has a prototype: void count (char sl, int *pUpper, pLower, poigit, pother) s [ is a
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Answer #1

Answer:-

As seen from the given problem the below is the required code

Code:-

void count(char s[], int *pUpper, int *pLower, int *pDigit, int *pOther)

{
int i;


*pUpper=*pLower=*pDigit=*pOther=0;
for(i=0;s[i]!='\0';i++)
{
if(96<s[i] && s[i]<123)
{
(*pLower)++;
}
else if(s[i]>64 && s[i]<91)
{
(*pUpper)++;
}
else if(s[i]>47 && s[i]<58)
{
(*pDigit)++;
}
else
{
(*pOther)++;
}
}
}

If you find difficulty to understand the code, please let me know then I will provide another code or I will do any modification. Hope it will helps. Please give Thumbs Up!! Thank you for posting the question, All the best

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pUI) FOU are to write a function which has a prototype: void count (char sl, int *pUpper, "pLower, "poigit, pother) s [ is a character string which may be of any length. Other arguments a...
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