Explain the results of the following cross in Drosophila: abnormal wing x abnormal wing The progeny: 53 - normal wing; 97 - abnormal wing. Explain the mode of inheritance and ratios of the progeny (us...
Explain the results of the following cross in Drosophila:
abnormal wing x abnormal wing
The progeny: 53 - normal wing; 97 - abnormal wing.
Explain the mode of inheritance and ratios of the progeny (use the chi-square test, if necessary). Write down the scheme of the cross and genotypes of the parents and offspring.
Homework Answers
Mode of inheritance - Autosomal recessive
Ratio of progeny from the above Punnett's square , normal wing : abnormal wing = 1 : 3
If the normal gene is AA ( homozygous ) , the abnormal will aa ( homozygous ) or Aa ( heterozygous ).
The crossing of 2 abnormal winged Drosophila produce normal and abnormal winged progenies . It is occured when heterozygous genotype was crossed. That is , Aa types .
Therefore ,the genotype of parents - Aa genotype .
The genotype of offsprings will have either aa or Aa for abnormal winged . And AA for normal winged .
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Explain the results of the following cross in Drosophila: abnormal wing x abnormal wing The progeny: 53 - normal wing; 97 - abnormal wing. Explain the mode of inheritance and ratios of the progeny (us...
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