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A 25 mg sample of Ciprofloxacin (Mw 331.35 g/mol, a = 9.083 X 103/M-cm) is dissolved in 1 liter of water and the absorbance o
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Answer #1

Absorbance, A = 0.56

Molar absorptivity, \epsilon = 9.083 x 103M-1cm-1

Although length is not given so we are going to take length in general as 1cm.

Conc., c = ?

A = \epsiloncl

c = 0.56 / (9.083 x 103M-1cm-1 x 1cm)

= 6.16 x 10-5M

Volume of original solution = 1L

Number of moles = Conc. x Volume

= 6.16 x 10-5mol.L-1 x 1L

= 6.16 x 10-5mol

Molar mass = 331.35 g/mol

Mass of pure sample = Number of moles x Molar mass

= 6.16 x 10-5mol x 331.35g.mol-1

= 20.43mg

Total mass of sample = 25mg

Purity = (Mass of pure sample / Total mass of sample) x 100

= (20.43mg / 25mg) x 100

= 81.72%

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A 25 mg sample of Ciprofloxacin (Mw 331.35 g/mol, a = 9.083 X 103/M-cm) is dissolved in 1 liter of water and the absorbance of a 10 ml sample is found to be 0.56 at 430 nm. What is the purity of...
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