Absorbance, A = 0.56
Molar absorptivity, = 9.083 x 103M-1cm-1
Although length is not given so we are going to take length in general as 1cm.
Conc., c = ?
A = cl
c = 0.56 / (9.083 x 103M-1cm-1 x 1cm)
= 6.16 x 10-5M
Volume of original solution = 1L
Number of moles = Conc. x Volume
= 6.16 x 10-5mol.L-1 x 1L
= 6.16 x 10-5mol
Molar mass = 331.35 g/mol
Mass of pure sample = Number of moles x Molar mass
= 6.16 x 10-5mol x 331.35g.mol-1
= 20.43mg
Total mass of sample = 25mg
Purity = (Mass of pure sample / Total mass of sample) x 100
= (20.43mg / 25mg) x 100
= 81.72%
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