F1. need help solving this problem. 1. (25 pts) Here's a neat theorem. Suppose that f la, b] [a, b] is continuous; then f will always map some s-value to itself (a so-called fixed point): i.e....
1. (25 pts) Here's a neat theorem. Suppose that f la, b] [a, b] is continuous; then f will always map some s-value to itself (a so-called fixed point): i.e. 3 c E (a, b) for which f(c)-c (a) Give a "visual proof" of this theorem. Hint: take your inspiration from our "visual proofs" of Theorem 15 and IVT And notice here that the domain and range of f are the same interval; this is important, and you need to use this fact carefully to make a nice picture.] (b) Now prove the above theorem rigorously, by applying Theorem 15. Hint: define a new function using our subtraction trick. Gazing at your picture from (a) might help a bit too.] (c) Of course, we don't know how many such points c there are; it all depends on er info we may have. For example, further suppose that f is differentiable on [a, b, and Vr, f'(x)メ1. Prove that f now cannot have more than one fixed point. Hint: try a proof by contradiction, and employ a theorem about derivatives. oth ints on Farth's
1. (25 pts) Here's a neat theorem. Suppose that f la, b] [a, b] is continuous; then f will always map some s-value to itself (a so-called fixed point): i.e. 3 c E (a, b) for which f(c)-c (a) Give a "visual proof" of this theorem. Hint: take your inspiration from our "visual proofs" of Theorem 15 and IVT And notice here that the domain and range of f are the same interval; this is important, and you need to use this fact carefully to make a nice picture.] (b) Now prove the above theorem rigorously, by applying Theorem 15. Hint: define a new function using our subtraction trick. Gazing at your picture from (a) might help a bit too.] (c) Of course, we don't know how many such points c there are; it all depends on er info we may have. For example, further suppose that f is differentiable on [a, b, and Vr, f'(x)メ1. Prove that f now cannot have more than one fixed point. Hint: try a proof by contradiction, and employ a theorem about derivatives. oth ints on Farth's