Question

2. (25pts) Two different brands of latex (water-based) paint are being considered for use in a large construction project. To

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Answer #1

Solution

Let

X = drying time (in hours) of Brand A paint.

Y = drying time (in hours) of Brand B paint.

Then, X ~ N(µ1, σ12) and Y ~ N(µ2, σ22), where σ12 = σ22 = σ2, say and σ2 is unknown.

Part (a)

i) Parameters of interest: (µ1, µ2) and (σ1, σ2) Answer 1

   Meaning of parameters of interest: (µ1, µ2) are the two population means and (σ1, σ2) are the two

   population standard deviations. Answer 2

ii) Modelling Assumptions: σ12 = σ22 = σ2, say and σ2 is unknown. Answer 3

    [Assumptions confirmed . Details at the end]

iii) Hypotheses:

Null: H0: µ1 = µ2 Vs Alternative: HA: µ1 µ2 Answer 4

Test Statistic:

t = (Xbar - Ybar)/{s√(2/n)} Answer 5

where

s2 = (s12 + s22)/2;

Xbar and Ybar are sample averages and s1,s2 are sample standard deviations based on n observations each on X and Y.

tcal = - 4.7155 Answer 5

Calculations

Summary of Excel calculations is given below:

n

22

Xbar

3.85

Ybar

4.959091

s1

0.799242

s2

0.766972

s^2

0.613517

s

0.783273

|tcal|

4.715485

α

0.05

tcrit

2.018082

p-value

2.67E-05

Critical Value = upper (α/2)% point of t2n – 2

= upper 2.5% point of t42

= 2.018 Answer 6

[obtained using Excel Function Statistical TINV]

p-value = P(t2n - 2 > | tcal |)

= P(|t42| > 4.7155)

= 2.67E-05 Answer 7

[obtained using Excel Function Statistical TDIST]

Conclusion:

Critical value approach: Since | tcal | > tcrit, H0 is rejected. Answer 8

p-value approach: Since p-value < α, H0 is rejected. Answer 9

Comparison: The conclusions arrived at with both approaches are identical. Answer 10

Interpretation

There is sufficient evidence to suggest that the

mean drying time are different for the two brands of paints. Answer 11

Part (b)

95% confidence interval for the difference in the two population means is:

(Xbar – Ybar) ± {(t2n – 2, 0.025)(s)√(2/n)}

= [- 1.6151, - 0.6122] [Brand A – Brand ] Answer 12

DONE

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