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Suppose you take a random sample of 30 individuals from a large population. For this sample, the sample mean is 4.2 and sample variance is 49. You wish to estimate the unknown population mean µ. (a) C...

Suppose you take a random sample of 30 individuals from a large population. For this sample, the sample mean is 4.2 and sample variance is 49. You wish to estimate the unknown population mean µ.

(a) Calculate a 90% confidence interval for µ.

(b) Calculate a 95% confidence interval for µ.

(c) Based on (a) and (b), comment on what happens to the width of a confidence interval (increase/decrease) when you increase your confidence level.

(d) Suppose your sample size is 100 instead of 30. The sample mean and variance are still 4.2 and 49 respectively. Calculate a new 90% confidence interval for µ.

(e) Based on (a) and (d), comment on what happens to the width of a confidence interval (increase/decrease) when you increase your sample size.

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Answer #1

Given that

sample n =30

sample mean μ,=4.2

sample variance σ^2= 49

standard deviation σ = 7

a)

Calculate high end confidence intenvaltotal High End -X tscore s/Nn High End = 4.2 + 1.6991 x 7-30 High End 4.21.6991 x 1.278

b)

High End a X+tscorea High End 4.2 2.0452 x 7N30 High End 4.2 2.0452 x 1.2780193008454 High End 4.2 2.613805074089 High End 6.

c)  The width increases as the confidence level increase

d)

Calculate high end confidence interval total: High End X+ zscores shn High End 4.21.645 7/N100 High End = 4.2 + 1.645 * 0.7 H

e)

Increasing the sample size decreases the width of confidence intervals

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