Suppose that, instead of forming a complete ring, the two ends of the wire are connected to the electrodes of a parallel-plate capacitor. The capacitor plates are circular with radius 1.0 cm and sepa...
A parallel plate capacitor is constructed with circular plates of radius 0.750 cm and plate separation 0.0500 mm. If the capacitor is connected across a 37.2 V source, find: a) the capacitance b) the surface charge on each plate c) The energy stored in the capacitor d) the electric field between the plates e) the energy density between the plates
Problem 3 Part A A copper wire with resistance 0.010 Ω is shaped into a complete circle of radius R 10 cm and placed in a long solenoid so that the axis of the solenoid and the axis of the wire loop coincide. The current in the solenoid is turned on and then slowly decreased. The magnetic field strength is initially B 0.750 T and subsequently decreases in time at the constant rate -0.035 T/s. (a) Calculate the induced emf...
A parallel plate capacitor with circular plates of radius R = 16.0 cm and plate separation d = 9.00 mm is being charged at the rate of 8.00 C/s. What is the displacement current through a circular loop of radius r = 21.00 cm centered on the axis of the capacitor? 8.00 You are correct. What is the displacement current through a circular loop of radius r = 3.00 cm centered on the axis of the capacitor? What is the...
Suppose that a parallel-plate capacitor has circular plates with radius R = 23 mm and a plate separation of 3.8 mm. Suppose also that a sinusoidal potential difference with a maximum value of 110 V and a frequency of 85 Hz is applied across the plates; that is, V = (110 V) sin[2π(85 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 26 mm and a plate separation of 4.1 mm. Suppose also that a sinusoidal potential difference with a maximum value of 170 V and a frequency of 82 Hz is applied across the plates; that is, V = (170 V) sin[2π(82 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 37 mm and a plate separation of 6.8 mm. Suppose also that a sinusoidal potential difference with a maximum value of 120 V and a frequency of 47 Hz is applied across the plates; that is, V = (120 V) sin[2π(47 Hz)t]. Find Bmax(R), the maximum value of the induced magnetic field that occurs at r = R.
Suppose that a parallel-plate capacitor has circular plates with radius R = 32 mm and a plate separation of 4.7 mm. suppose also that a sinusoidal potential difference with a maximum value of 160 V and a frequency of 60 Hz is applied across the plates: that is, V = (160 V) sin[2 n(60 Hz)t] Find B_max, the maximum value of the induced magnetic that occurs at r = R.
A parallel-plate capacitor is constructed of two horizontal 17.2-cm-diameter circular plates. A 1.0 g plastic bead with a charge of -4.0 nC is suspended between the two plates by the force of the electric field between them.
A parallel-plate capacitor has closely spaced circular plates of radius R = 2.00 cm. Charge is flowing onto the positive plate at the rate / = 1.36 A. The magnetic field at a distance r = 2.00 cm from the axis of the plates is approximately 136 mt. 88.3 mT. 256 mT. 16.5 mT. 457 mT.
A 0.160–A current is charging a capacitor that has circular plates 11.8 cm in radius. The plate separation is 4.00 mm. (a) What is the time rate of increase of electric field between the plates? V/(m·s) (b) What is the magnetic field between the plates 5.00 cm from the center? T