Question

Hi could someone help me come up with the workout to the question? I know the answer I just don’t know my way around it. Thank you in advance!

to reject the claim. Probability öf Tyen 11) A trucking firm suspects that the mean lifetime of a certain tire it uses is less than 37,000 miles. To 11) check the claim, the firm randomly selects and tests 54 of these tires and gets a mean lifetime of 36,650 miles with a standard deviation of 1200 miles. At a 0.05, test the trucking firm's claim. A) test statistic -2.14; critical value z0 -1.645; reject Ho: There is sufficient evidence to support the trucking firm's claim. (ANSWER) B) test statistic-2.14; critical value z01.645; do not reject Ho: There is not sufficient evidence to support the trucking firm's claim.

Answer 1

H0: Null Hypothesis: 37000

μ>

HA: Alternative Hypothesis: $\mu <$ 37000

SE= s/$\sqrt{n}$

= 1200/ = 163.2993

V54

Test statistic is given by:

Z = (36650 - 37000)/163.2993 = - 2.14

$\alpha$ = 0.05

From Table, critical value of Z₀ = - 1.645

Since calculated value of Z = - 2.14 is less than critical value of Z = - 1.645, the difference is significant. Reject null hypothesis.

Correct option:

test statistic = - 2.14; critical value Z₀ = - 1.645; reject H0; There is sufficient evidence to support the trucking firm's claim.