6. Whatdetermineswhethertouseat-distributionoranormaldistribution for finding a confidence interval for μ ?
So,
t dist is used when population standard deviation is unknown
while
z normal is used when we know the value of population standard deviation
6. Whatdetermineswhethertouseat-distributionoranormaldistribution for finding a confidence interval for μ ?
Construct the confidence interval for the population mean μ. Construct the confidence interval for the population mean μ 0.98, x: 5.9, σ: 0.6, and n: 44 A 98% confidence interval for μ is OD (Round to two decimal places as needed.)
.Find a 99% confidence interval for μ if n-100. b, Find a 99% confidence interval for μ if n 400. e. Find the widths of the holding the confidence a.The 99% confidence interval for μ if n-100i8 approxmatelyOO Round to three decimal places as needed.) b. The 99% confidence interval p if n-400 is approximately Round to threç decimal places as needed.) 0 1 of 2 O A. Quadrupling the sample size while holding the confidence coefficient fixed increases the...
1. The mayor is interested in finding a 90% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 209 residents whose mean number of pounds of trash generated per person per week was 34.5 pounds and the standard deviation was 7.5 pounds. Round answers to 3 decimal places where possible a.With 90% confidence the population mean number of pounds per person per week is between ___...
6.1.23 construct the confidence interval for the population mean μ c = 0.98, x̅ = 15.7, σ = 4.0, and n=65 A 98% confidence interval for μ is OD (Round to one decimal place as needed.)6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed.)
A statistician constructed a confidence interval for the mean μ of a population and the result was the interval (25,30). Which of the following statements is/are true? There is a 0.9 probability μ is between 25 and 30. If 100 random samples of the same size are picked and a 90% confidence interval is calculated from each one, then μ will be in 90 of those 100 confidence intervals. If 90% confidence intervals are calculated from all possible samples of...
In finding the (1 – a)%confidence interval for the mean of a Normal distribution, we are interested in finding the confidence interval with the O shortest average length O average length O shortest length O none of the above O widest length
and i need help finding the upper bound confidence interval as well Construct a confidence interval of the population proportion at the given level of confidence. x = 120, n = 1200, 95% confidence Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). The lower bound of the confidence interval is LI. (Round to three decimal places as needed.)
Use the t-distribution to find a confidence interval for a difference in means μ 1 - μ 2 given the relevant sample results. Give the best estimate for μ 1 - μ 2 , the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ 1 - μ 2 using the sample results x ¯ 1 = 10.0 , s 1 = 2.2...
Use the t-distribution to find a confidence interval for a difference in means μ 1 - μ 2 given the relevant sample results. Give the best estimate for μ 1 - μ 2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ 1 - μ 2 using the sample results x ¯ 1 = 5.5 , s 1 = 2.3 ,...
Use the t-distribution to find a confidence interval for a difference in means μ 1 - μ 2 given the relevant sample results. Give the best estimate for μ 1 - μ 2 , the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ 1 - μ 2 using the sample results x ¯ 1 = 10.0 , s 1 = 2.2...