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In finding the (1 - α)% confidence interval for the mean of a Normal distribution, we are interested in finding the confidence interval with the average length.
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In finding the (1 – a)%confidence interval for the mean of a Normal distribution, we are...
A researcher is interested in finding a 95% confidence interval for the mean number of times...
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 141 students who averaged 25.7 texts per day. The standard deviation was 21.2 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a tv distribution. 0 and b. With 95% confidence the population mean number of texts per day is between texts. c. If many groups of 141...
For most distributions, we can use the normal distribution to make a confidence interval for a...
For most distributions, we can use the normal distribution to make a confidence interval for a populatiorl mean provided that the population standard deviation σ is known and the sample size is: O greater than or equal to 30. O greater than 100 O greater than 30. O less than 25.
A researcher is interested in finding a 98% confidence interval for the mean number of times...
A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 126 students who averaged 34.8 texts per day. The standard deviation was 18.7 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution and texts. b. With 98% confidence the population mean number of texts per day is between c. If many groups of 126...
A fitness center is interested in finding a 98% confidence interval for the mean number of...
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 263 members were looked at and their mean number of visits per week was 2.1 and the standard deviation was 2.9. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean...
You are interested in finding a 98% confidence interval for the mean number of visits for...
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. 25 12 27 6 8 13 25 a. To compute the confidence interval use a distribution. 5 24 9 18 25 10 and b. With 98% confidence the population mean number of visits per physical therapy patient is between visits. c. If many groups of 13...
A fitness center is interested in finding a 95% confidence interval for the mean number of...
A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 240 members were looked at and their mean number of visits per week was 2.3 and the standard deviation was 1.7. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution. b. With 95% confidence the...
A fitness center is interested in finding a 95% confidence interval for the mean number of...
A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 265 members were looked at and their mean number of visits per week was 2.5 and the standard deviation was 1.6. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? t or z distribution. b. With 95% confidence...
You are interested in finding a 98% confidence interval for the mean number of visits for...
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 15 10 1621 27 20 19 6 23 28 15 18 27 a. To compute the confidence interval use a ? distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
1. The mayor is interested in finding a 90% confidence interval for the mean number of...
1. The mayor is interested in finding a 90% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 209 residents whose mean number of pounds of trash generated per person per week was 34.5 pounds and the standard deviation was 7.5 pounds. Round answers to 3 decimal places where possible a.With 90% confidence the population mean number of pounds per person per week is between ___...
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 141 students who averaged 25.7 texts per day. The standard deviation was 21.2 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a tv distribution. 0 and b. With 95% confidence the population mean number of texts per day is between texts. c. If many groups of 141...
For most distributions, we can use the normal distribution to make a confidence interval for a populatiorl mean provided that the population standard deviation σ is known and the sample size is: O greater than or equal to 30. O greater than 100 O greater than 30. O less than 25.
A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 126 students who averaged 34.8 texts per day. The standard deviation was 18.7 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution and texts. b. With 98% confidence the population mean number of texts per day is between c. If many groups of 126...
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. 25 12 27 6 8 13 25 a. To compute the confidence interval use a distribution. 5 24 9 18 25 10 and b. With 98% confidence the population mean number of visits per physical therapy patient is between visits. c. If many groups of 13...
A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 240 members were looked at and their mean number of visits per week was 2.3 and the standard deviation was 1.7. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution. b. With 95% confidence the...
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 15 10 1621 27 20 19 6 23 28 15 18 27 a. To compute the confidence interval use a ? distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
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