In 1947 a large collection of papyrus scrolls, including the oldest known manuscript version of the Old Testament, was found in a cave near the Dead Sea; they have come to be known as the “Dead Sea Scrolls”. The scroll containing the book of Isaiah was dated in 1994 using the radiocarbon technique and it was found to contain between 75% to 77% of the initial level of carbon 14. Radioactive decay is modeled by the function
m (t) = m0 e-kt
where m0 is the initial mass of a radioactive substance, k is the relative decay rate and t is time.
(a) Show that if the half-life of carbon 14 is 5700 years then k ≈ 1.216 × 10-4. Half-life is the time it takes for half of the radioactive isotopes to decay.
(b) Between which dates was the scroll written?
(c) If the scroll will be dated today how much carbon 14 will it contain (as a percentage of the initial level)?
write neatly and show all of the steps in an organized way.
In 1947 a large collection of papyrus scrolls, including the oldest known manuscript version of the Old Testament, was found in a cave near the Dead Sea; they have come to be known as the “Dead Sea Sc...
In 1947 a large collection of papyrus scrolls, including the oldest known manuscript version of portions of the Old Testament, was found in a cave near the Dead Sea: they have come to be known as the 'Dead Sea Scrolls'. The scroll containing the book of Isaiah was dated in 1994 using the radiocarbon technique;^2 it was found to contain between 75% and 77% of the initial level of carbon 14. Between which dates was the scroll written?
In 1947 samples of the Dead Sea Scrolls were analyzed by carbon dating. It was found that the carbon-14 present had an activity (rate of decay) of 11 d/min.g (where d = disintegration). In contrast, living material exhibit an activity of 14 d/min•g. How old is the Dead Sea Scrolls? Hint: the decay rate is proportional to the amount of the radioactive isotope present. 2 = 1.21 X 10-4 yr1