Question

Java

I just need the answer to the questions, not the whole implemented code please

You have an object of the RandomAccessFile class named empRaf. It refers to a physical file that contains a company's employee records. Each employee record has:

an int field named empID which points to its location in the file

a 20 character last name

a 15 character first_name

a hire date stored as an int

a 3 character job code

The empID values begin at 1, but the first record in the file begins at byte 0.

1. Calculate the length of this record.

2. Write a statement that positions the file pointer at the beginning of the record that has empID 20

Answer 1

1. Calculate the length of this record.

Ans:

First record empId: 0. (1 letter)

a 20 character last name (20 letters)

a 15 character first_name (15 letters)

a hire date stored as an int (13 letters)

a 3 character job code (3 letters)

And in between we need a delimiter to split the records. The record should be similar to below:

1,fname,lastname,jobcode

So there should be three more delimiter characters.

total lengtjh = 1+20+15+13+3+3= 45

2. Write a statement that positions the file pointer at the beginning of the record that has empID 20

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class FileReader {
    public static void main(String[] args) throws FileNotFoundException {
        Scanner sc = new Scanner(new File("data.txt"));
        String line= "";
        while(sc.hasNextLine()){
            line = sc.nextLine();
            if(line.split(",")[0].equals("20")){
                System.out.println(line);
                break;
            }
        }
    }
}

Please comment if you need any help.