Question

AGGREGATE PLANNING
Garden Hub makes a single product, a garden tool that sells for $40. Garden Hub starts with 1000 of these tools in inventory and is expected to end with at least 500 in stock. Garden Hub can temporarily backlog demand for a cost, but at the end of the time horizon, they require their backlog to be zero – This is an important constraint to remember- if we forget it, we will get strange results . Production costs are based on parts and labor with no machine capacity issues – They start with 80 employees can hire or fire workers for a cost. – Workers get regular pay whether they are producing or not. There are 20 days of production per month, each month. – We can have workers work overtime (no more than 10 hrs/mo per worker) for extra $ – We can also subcontract production out and pay a flat fee (in lieu of labor + materials). Garden Hub would like to generate a 6-month plan that maximizes profits (revenue net of costs) – For now we can just minimize costs, if we have no influence over demand. Here’s the demand - see the seasonality?

Note: subcontracting costs includes all materials and labor.

ONLY FORMULATE THE PROBLEM, NO NEED TO SOLVE.

Month January February Item Cost Demand Forecast $10/unit Materials 1600 $2/unit/month Inventory holding cost 3,000 Marginal

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Answer #1

SOLUTION

Firstly, our given data is:

Item Materials Inventory Cost Month January February Demand Forecast $10/unit 1600 $2/unit/month 3,000 holding cost Marginal

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The decision variables for month, t = 1 to 6 (January to June) will be:

Wt=Workforce size for month t
Ht=Number of employees hired at the beginning of month t
Lt=Number of employees laid off at the beginning of month t
Pt=Production in month t
It=Inventory at the end of month t
St=Number of units stocked out or backlogged at the end of month t
Ct=Number of units subcontracted for month t
Ot=Number of overtime hours worked in month t

Total cost = (Regular-time labor cost + Overtime labor cost + Cost of hiring and layoffs + Cost of holding inventory + Cost of stocking out + Cost of subcontracting + Material cost)

Regular-time labor cost per worker = $4/hour*8hrs/day*20days/month = $640/month

So, total regular-time labor cost = $640/month*Number of workers = $640*Wt

Overtime labor cost = $6*Ot

Cost of hiring and layoffs = $300*Ht + $500Lt [It costs $300 to train any new hire and $500 for every worker fired]

Cost of holding inventory = $2*It [Units at end of month is It and cost of holding one unit of inventory is $2]

Similarly, Cost of stocking out = $5*St

              Cost of subcontracting = $30*Ct

Materials cost = $10/unit * Production number of units = $10*Pt

So overall cost = 640Wt + 6Ot + 300Ht + 500Lt + 2It + 5St + 30Ct + 10Pt

Hence, objective function is:

Minimize Z = 640Wt + 6Ot + 300Ht + 500Lt + 2It + 5St + 30Ct + 10Pt

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The problem of minimization is subject to constraints:

1. Workforce constraints:

Wt = Wt-1 + Ht - Lt (Workforce at any month is the workforce in the previous month + Number of workers hired - NUmber of workers fired) (With W0 = 80 as initially we have 80 workers)

2. Production capacity constraints:

Pt = 40Wt + Ot/4 [Wt are the number of workers and each can worker can make 2 units in a day and hence 40 units in a month. Labor hours for each unit is 4 hours and hence each day a worker can make 2 units and there are 20 production days in a month] [Every 4 hours will give 1 unit, hence number of overtime hours/4 will give number of units through overtime labor]

3. Inventory balance constraint:

It-1 + Pt + Ct - Dt - St-1 = It - St [Inventory at the beginning of the month + Number of units produced + Number of units through subcontract - Demand fulfilled for that month - Demand for previous month fulfilled due to stockout in previous month = Ending inventory for this month - Stockout in this month] [Also I0 = 1000 as we start with 1000 units]

I6 >= 500 [There need to be at least 500 units at the end of the horizon time period that is six months in this case]

4. Overtime limit constraints:

Ot <= 10Wt [Overtime constraints say that overtime hours cannot be more than 10 hours per worker]

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So full problem formulation is:

Minimize Z = 640Wt + 6Ot + 300Ht + 500Lt + 2It + 5St + 30Ct + 10Pt

subject to

Wt = Wt-1 + Ht - Lt

W0 = 80

Pt = 40Wt + Ot/4

It-1 + Pt + Ct - Dt - St-1 = It - St

I6 >= 500

Ot <= 10Wt

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Kindly comment in case of any questions. Thanks :)

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