9. Consider the graph in problem 8, call it G. a) Find at least one non-trivial graph automorphism on G. That is, find a graph isomorphism f:G -G. Show that there are bijective mappings g: V(G)-V...
2. a) Determine whether the following graphs are isomorphic or not. If so write an isomorphism, if not explain why. 1 b 2 a 6 3 f d 5 4 e Graph A Graph B. b) Is the graph A bipartite. If not, find a vertex v such that A - v bipartite? c) Does the graph A have an Eulerian circuit? If not find an edge e such that A - e has an Eulerian circuit.
Hi, I could use some help for this problem for my discrete math class. Thanks! 18. Consider the graph G = (V, E) with vertex set V = {a, b, c, d, e, f, g} and edge set E = {ab, ac, af, bg, ca, ce) (here we're using some shorthand notation where, for instance, ab is an edge between a and b). (a) (G1) Draw a representation of G. (b) (G2) Is G isomorphic to the graph H -(W,F)...
er (a) Let G be a connected graph and C a non-trivial circuit in G. Prove directly that if an edge ={a, b} is removed from then the subgraph S CG that remains is still connected. Directly' means using only the definitions of the concepts involved, in this case 'connected' and 'circuit'. Hint: If r and y are vertices of G connected by path that includes e, is there an alternative path connecting x to y that avoids e? (b)...
Question 1: Given an undirected connected graph so that every edge belongs to at least one simple cycle (a cycle is simple if be vertex appears more than once). Show that we can give a direction to every edge so that the graph will be strongly connected. Question 2: Given a graph G(V, E) a set I is an independent set if for every uv el, u #v, uv & E. A Matching is a collection of edges {ei} so...
Question 1# (a) Let G be a connected graph and C a non-trivial circuit in G. Prove directly that if an edge e fa, b is removed from C then the subgraph S C G that remains is still connected. "Directly' means using only the definitions of the concepts involved, in this case connected' and 'circuit'. Hint: If z and y are vertices of G connected by path that includes e, is there an alternative path connecting x to y...
Problem 8. (2+4+4 points each) A bipartite graph G = (V. E) is a graph whose vertices can be partitioned into two (disjoint) sets V1 and V2, such that every edge joins a vertex in V1 with a vertex in V2. This means no edges are within V1 or V2 (or symbolically: Vu, v E V1. {u, u} &E and Vu, v E V2.{u,v} &E). 8(a) Show that the complete graph K, is a bipartite graph. 8(b) Prove that no...
need help filling in the code def prim(G): Use Prim's algorithm to find a MST for the graph G … # Initialize tree T with a single vertex and no edges v = next(iter( )) # while the vertex set of T is smaller than the v+tex set of G, # (i.e. while the vertex set of T is a proper subset of the vertex set of G), find the edge e with minimum weight so that # Tte is...
Say that we have an undirected graph G(V, E) and a pair of vertices s, t and a vertex v that we call a a desired middle vertex . We wish to find out if there exists a simple path (every vertex appears at most once) from s to t that goes via v. Create a flow network by making v a source. Add a new vertex Z as a sink. Join s, t with two directed edges of capacity...
8, (10 pts) Show that given a directed graph G = (V,E) already stored in adjacency matrix form, determining if there is a vertex with in-degree n - 1 and out-degree 0 can be done in O(n) time where n is the number of vertices in V. 8, (10 pts) Show that given a directed graph G = (V,E) already stored in adjacency matrix form, determining if there is a vertex with in-degree n - 1 and out-degree 0 can...
Other answer is incorrect Problem 1. (15 points) Consider an undirected connected graph G = (V, E) with edge costs ce > 0 for e € E which are all distinct. (a) [8 points). Let E' CE be defined as the following set of edges: for each node v, E' contains the cheapest of all edges incident on v, i.e., the cheapest edge that has v as one of its endpoints. Is the graph (V, E') connected? Is it acyclic?...