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Listed below are amounts (in millions of dollars) collected from parking meters by a security company in a cortain city. A la
Listed below are amounts (in millions of dollars) collected from parking meters by a security company in a certa of the compa
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Listed below are amounts (in millions of dollars) collected from parking meters by a security company in a cortain city. A larger data set was used to convict 5 r ted data listed he of the company of grand larceny, Find the mean and median for each of the two samples and then compare the two sets of results. Do the lim evidence of stealing by the security company's employees? 1.4 1.6 1.4 1.6 1.3 1.1 1.5 1.1 1.1 1.70 2.1 1.7 1.9 1.5 1.9 2.2 1.7 1.5 15 18 Security Company Other Companies: Compare the results. Choose the correct answer below. median for the collections performed by other companies are both lower than the mean and the median for the security company O B. The median is lower for the collections performed by other companies, but the mean is lower for the security company O C. The mean and median appear to be roughly the same for all collections. O D. The mean and the median for the security O E. The mean is lower for the security company, but the median is lower for the collections performed by other companies or the collections performed by other oom panies. company are both lower than the mean and the median
Listed below are amounts (in millions of dollars) collected from parking meters by a security company in a certa of the company of grand larceny. Find the mean and median for each of the two samples and then compare the two city. A larger data set was used to convict 5 members evidence of stoaling by the security company's employees? rse 1.4 1.6 1.4 1.6 1.3 1.1 1.5 1.1 1.1 1.70 2.1 1.7 1.9 1.5 1.9 2.2 1.7 1.5 1.5 1.8 Security Company: Other Companies: Но security company are both lower than the mean and the median for the collections performed by other companies E. The mean is lower for the secunity company, but the median is lower for the collections performed by other companies Do the limit data listed here show evidence of stealing by the security company's em O A. The sampie size is not large enough to show any meaningful results ce is some evidence of stealing by the security company's an OB. Since the C. Since the security company does not appear to have collected lower revenue than the other companies, there is no evidence of stealing by the secunity company's employees Since the data is not matched, there is no evidence of stealing by the security company's employees. O D.
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Answer #1

the mean for the security company is $ 1.38 million and the mean for the other companies is $ 1.78 million.

the median for the security company is $ 1.40 million and the median for the other companies is $ 1.75 million.

correct option is:

the mean and median for the security company are both lower than the mean and median for the collections performed by other companies.[option D]

correct option is:

the sample is not large enough to show any meaningful result.[option A]

there is no evidence of stealing , because even though the mean and median amount collected by security companies are less than that of other companies ,the difference is not large enough and could possible be due to chance....so it will be quite appropriate  if the sample size be large enough to take any decision..as here it is too small,i.e 10.

****NECESSARY CALCULATIONS FOR MEAN AND MEDIAN:-

mean - i, where i=1,2,.......n

here for security company, n=10  Xi = 1.4 + 1.6 + 1.4 + 1.6 + 1.3 + 1.1 + 1.5 + 1.1 + 1.1 + 1.7 13.8
13.8 =-= 10 1.38 so, mean

arranging the data we get 1.1 , 1.1 , 1.1 , 1.3 , 1.4 , 1.4 , 1.5 , 1.6 , 1.6 , 1.7

for n=10(even number)

median--* [-th + (一+1)th.observationl

10 1 10 ation5th +6th.obs ー.. * [_th + (ー+ 1)th.observation] =-*

=(1.4+1.4)/2=1.4

for other companies,

n=10

〉 т = 2.1 + 1.7 + 1.9 + 1.5 + 1.9 + 2.2 + 1.7 + 1.5 + 1.5 + 1.8 17.8

17.8 10 1.18 so, mean

arranging the data we get 1.5 , 1.5 , 1.5 , 1.7 , 1.7 , 1.8 , 1.9 , 1.9 , 2.1 , 2.2

median--* [-th + (一+1)th.observationl

10 1 10 ation5th +6th.obs ー.. * [_th + (ー+ 1)th.observation] =-*

=(1.7+1.8)/2=1.75

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Answer #2

1.7+1.1+1.7+1.1 +1.5+1.3+1.6+1.3+1.2

source: math
answered by: bini
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