(a)
Single shear:
P=fv(0.785x1)
P=0.6x36x0.785=16.956 kips
(b)
Double shear=twice of single shear
double shear=33.912 kips
(c)
Fu=120 ksi for A325 bolts
Ft=0.75Fu
Ft=0.75x120=90
Capacity=0.75x90x0.785=53 kips
(d)
tb=1.0625 in
Lc=2-1.0625/2=1.46875 in
Capacity=0.75x1.2x1.46875x0.5x58=38.3 kips
(e)
tb=1+1/16=1.0625 in
Lc=3-1.0625=1.9375 in
Capacity=0.75x1.2x1.9375x0.5x58=50.65 kips
Limit=2.4dtFu=2.4x1x0.5x58=69.6 kips
5. Using AISC Steel Construction Manual, find the following design strengths of 1-inch Group A bolts on A36 gusset plates, type N, with STD holes, 3" bolt spacing and 2" edge distance: (5...
Steel Design 2. (50 pts) Design an A36-steel tension member 16 ft long consisting of two channels, bolted through their webs to a single 1 inch gusset plate, to transmit 75 kips DL and 93 kips LL. The bolts are 7/8 in. Bolt spacing 4 inch and bolt edge distance 3 inch. In addition to checking block shear in the channels, design the thickness of the gusset plate to resist block shear.
3. A C 9x15 is to be used as a tension member. The channel is bolted to a 5/8 in gusset plate with 7/8 inch diameter, A307 bolts. The tension member is AS72 Grade 50 steel and the gusset plate is A36. Follow Figure 3. (a) Check all spacing and edge distance irements; (b) Compute the design strength based on shear and bearing; and (c) Compute the allowable strength based on shear and bearing. 23" 3" 3" С 9x 15...
can i have this one solved by using AISC steel manual plzzzz? Problem 1. A lap connection shown below should carry the factored axial load of 120 kips. The plates 3/8 x 7 and 5/16 x 7 are made of A36 (Fu=58 ksi) steel. Design the bolted connection: (a) Select bolt material and diameter: (b) Determine number of bolts using shear capacity of bolt; (c) Place the bolts with min/max requirements; (d) Calculate the bearing strength of bolts and determine...