Answer: option A is correct answer
Correct sequence of gene: ubm
Now we want to calculate the distance between them
Between b and m
Step1: Find out single cross over between b and m
uu+ bb mm+ :68 and uu bb+ mm: 82
Now,
Distance between two gene= [(number of single cross over+number of double cross over)/total number of progeny]×100
For b and m= [(68+82+7+3)/2000]×100
= 8 cM
Distance between u and b
Single cross over between the u and b
uu+ bb+ mm+: 172 and uu bb mm: 128
For u and b= [(172+128+7+3)/2000]×100
=15.5 cM
number 5 please show work and explain! dce 4) Assume a three-point cross in which uu bbt mm* was crossed to uu* bb mm and the offspring had the following genosypes 782 128 uu-bbt-mm er of the gen...