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Problem 3: The length of time to failure (in hundreds of hours) for a transistor is a random variable X with the CDF given be

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Answer #1

a)

b)

pdf =f(X)=(d/dx)*F(X)=(d/dx)*(1-e-x^2) =2xe-x^2   for x>=0

c)

P(X<=0.4) =1-e-0.4^2 =0.1479

d)

P(X>2)= 1-e-2^2 =0.0183

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Problem 3: The length of time to failure (in hundreds of hours) for a transistor is a random variable X with the CDF given below: 2 F(x)lTe; x20 (a) Plot the CDF by hand. (b) Derive the pdf of this r...
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