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th is a weld inspector at a shipyard. He knows from keeping track of good and substandard welds that for the afternoon shift
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Answer #1

We can use Poisson distribution (Exact distribution is binomial) here since the population 7,500 is large and the sample size is 300. The parameter of Poisson is \lambda =300\times 0.05=15 .

The Poisson PMF is

P\left ( X=x \right )=e^{-\lambda }\frac{\left (\lambda \right ) ^x}{x!};x=0,1,2,3,..... Here = 15 . The probability,

x=0 19、15(15) x! x=0 P(X 〈 20) = 0.8752

The R command below.

> ppois(19,15)
[1] 0.8752188

The Exact probability is (using binomial distribution)

> pbinom(19,300,0.05)
[1] 0.8809531

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th is a weld inspector at a shipyard. He knows from keeping track of good and substandard welds that for the afternoon shift 5% ofall welds done will be substandard. If Smith checks 300 of th...
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