d) Find the area between the two curves (the shaded region). 2 + (2 r=2+cos 2θ ra sin 2θ
d) Find the area between the two curves (the shaded region). 2 + (2 r=2+cos 2θ ra sin 2θ
Use trigonometric identities to solve the equation
2sin(2θ)-2cos(θ)=0 exactly for 0≤θ≤2π.
A.) What is 2sin(2θ) in terms of sin(θ)and cos(θ)?
B.) After making the substitution from part 1, what is the
common factor for the left side of the expression
2sin(2θ)-2cos(θ)=0 ?
C.) Choose the correctly factored expression from below.
a.)
b.)
c.)
d.)
We were unable to transcribe this imageAsin(e) cos(O) = 2cos(e) We were unable to transcribe this imageWe were unable to transcribe this image
g and h
g. sin+1-0 sin 2θ-3 cos 26(to find the solutions in [0,2π), use a calc. for this one only) i, sin 2e-V3 cos θ 0
Prove the Dirichlet Kernel: 1/2 + cos(θ) + cos(2θ) + cos(3θ) + ... + cos(Nθ) = sin[(N+1/2)θ] / 2sin(θ/2) for all θ ≠ 2πn
Solve the equation in the interval [0°, 360°). 4 sin^2θ = 3 csc θ = 1 + cot θ 3 sin^2θ - sin θ - 4 = 0 2 cos^3θ = cos θ
How to graph atomic orbital: sin(2θ)cos(φ)
3. E valuate the integral by converting to polar coordinates: 0
3. E valuate the integral by converting to polar coordinates: 0
Find the area of the region outside of r = cos 2θ and inside r= 1 + sinθ. Graph both on the same graph. Shade the region.
ecos (20) cos e Establish the identity cos + cos (30) sin 0+ sin (30) cot (20) Choose the correct sequence of steps to establish the identity cos 0 + cos (30) 2 cos (20) cos (20) OA sin 0+ sin (30) cot (20) 2 cos (20) sin (20) B. cos 0 + cos (30) sin 0 + sin (30) = 2 sin (20) cos e = cot (20) Ос. = cos 0 + cos (30) 2 sin cos (20)...
Solve the equation in the interval [0°, 360°). sin^2θ - sin θ - 12 = 0 sin 2θ = -sin θ 2 cos2θ + 7 sin θ = 5